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xxMikexx [17]
3 years ago
13

What do the interquartile ranges (IQRs) tell you about how the teams race? Explain your thinking.

Mathematics
1 answer:
nadya68 [22]3 years ago
7 0

Answer:

The medians of all three teams can show the overall skill level of the teams. For example, the medians only vary between 47 and 48. This can show that most team members have around the same experience (since they have around the same median). The red team was the best in terms of time, but they don't vary much from their opposing teams.

Step-by-step explanation:

(Can also add more references to the chart and rank the teams in term of time )

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Maci is paid biweekly and earns $1500 each paycheck. What is his yearly salary?
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Will and Mohammed are playing a game where they roll a fair six-sided die and a fair four-sided die and try to predict the outco
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A proof of the Alternate Interior Angles Theorem, using parallel lines a and b with transversal m, is shown below.
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What is two and two fourths plus one third
kkurt [141]

Answer:

2 5/6

Step-by-step explanation:

2 2/4 + 1/3

First, you have to make the bottoms of the fraction the same, by figuring out the lowest common denominator. In this case it would be 12. 4x3 = 12. 3x4 = 12.

Multiply the top number by the same number you multiplied the bottom by.

We multiplied the 4 by 3, so we would also multiply the 2 by 3 (which would be 6).

Do the same for the second fraction. 1x4 = 4.

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8 0
3 years ago
Approximate the change in the volume of a sphere when its radius changes from r = 30 ft to r=10.1 ft [v(r)=4/3Ï€r^3]. When r cha
ella [17]

Answer: ∆V for r = 10.1 to 10ft

∆V = 40πft^3 = 125.7ft^3

Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________

[v(r)=4/3Ï€r^3].

Step-by-step explanation:

Volume of a sphere is given by;

V = 4/3πr^3

Where r is the radius.

Change in Volume with respect to change in radius of a sphere is given by;

dV/dr = 4πr^2

V'(r) = 4πr^2

V'(10) = 400π

V'(10.1) - V'(10) ~= 0.1(400π) = 40π

Therefore change in Volume from r = 10 to 10.1 is

= 40πft^3

Of by direct substitution

∆V = 4/3π(R^3 - r^3)

Where R = 10.1ft and r = 10ft

∆V = 4/3π(10.1^3 - 10^3)

∆V = 40.4π ~= 40πft^3

And for R = 30ft to r = 10.1ft

∆V = 4/3π(30^3 - 10.1^3)

∆V = 34626.3πft^3

3 0
3 years ago
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