Answer:

Step-by-step explanation:
The volume of a sphere is given by :

The rate of change of volume means,

We have, 
So,

So, the volume is increasing at the rate of
.
3(23) really means 3*23, or just 3 multiplied by 23. For example: "Jana has 23 dollars. Her friend John has $23, and his friend Jacob also has 23 dollars. How much money do they have all together?" To solve this problem mentally, you could break 3*23 into two numbers you're familiar with multiplying, like 20 and 3, and then add the numbers together. For example: 3*20 + 3*3. 3*20=60, 3*3=9, and 60+9=69. So, 3*23=69.
a. The reason why this question is a binomial experiment is based on the fact that it is made up of an independent sample, it has a number that is fixed and a probability.
Each event is made up of two outcomes and they are random with the same success rate.
<h3>b. How to solve probability that exactly 5 had a bachelor</h3>
we have the following data n = 12, p = 0.27 and k = 5
We have to use the function to solve electronically
binompdf(n,p,k)
input the values
= binompdf(12,0.27,5)
This gives us
= 0.1255
<h3>(C) Probability that fewer than 5 have bachelor</h3>
We use the formula below
= binompdf(12,0.27,5-1)
This is = 0.7984
D. Probability of at least 5
1 - probability of fewer than 5
= 1 - 0.7984
= 0.2016
How to solve for the Mean = n*p
n = 12 , p = 0.27
Mean = 12*0.27 = 3.24
and
standard deviation = √npq
n = 12, p = 0.27 , q = 1- 0.27
= 0.73
sd = √12*.27*.73
= 1.54
Read more on binomial experiment here:
brainly.com/question/9325204
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Answer:
N= -2
Step-by-step explanation:
N+10=8
-10= -10
N= -2
<h3>Answer:</h3>
2/15
<h3>Explanation:</h3>
There are 8C2 = 28 ways to choose 2 dimes from the 8 dimes in Annie's purse. There are 21C2 = 210 ways to choose 2 coins from the 21 coins in Annie's purse.
Of the 210 ways to choose 2 coins, 28 of the choices will result in 2 dimes being chosen. The probability of choosing 2 dimes is 28/210 = 2/15.
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<em>Comment on nCk</em>
The number of ways to choose k objects from n, when order does not matter, is ...
... n!/(k!(n -k)!)
For the computations above, we have ...
... 8C2 = 8·7/(2·1) = 28
... 21C2 = 21·20/(2·1) = 210