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3 years ago

SOMEONE PLEASE HELP FOR A KISS

Mathematics

1 answer:

Svetllana [295]3 years ago

7 0

Answer:

The answer is C.

Step-by-step explanation:

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Evaluating express 6 Evaluate 13 + - when y = 6. y

Step2247 [10]

Step-by-step explanation:

how i think this question is

13+ -y

y=6

= 13 + -6

therefore the answer is 7

7 0

3 years ago

What is the vertex of the quadratic function fix=(x-8)(x-2)

VikaD [51]

Answer:

Vertex: (5, -9)

Step-by-step explanation:

fix = (x-8)(x-2)

fix = x^2 - 2x - 8x + 16

fix = x^2 - 10x + 16

a = 1, b = -10, and c = 16

To find vertex:

x = -b/2a

x = -(-10)/2(1)

x = 10/2

x = 5

y = 5^2 - 10(5) + 16

y = 25 -50 + 16

y = -9

Vertex: (5, -9)

8 0

3 years ago

I think this is my last one! Will give Brainliest! DUE TODAY!!!Will give everything good and will make smartest answer WITH WORK

const2013 [10]

Answer:

Step-by-step explanation:

$m=\frac{y_2 - y_1 }{x_2 - x_1} = \frac{275-300}{5-0} = \frac{-25}{5} = -5$

The item is discounted by $5 per week.

4 0

3 years ago

Please help me

Hitman42 [59]

By using algebra properties and trigonometric formulas we find that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equivalent to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ .

<h3>How to prove a trigonometric equivalence by algebraic and trigonometric procedures</h3>

In this question we have trigonometric expression whose equivalence to another expression has to be proved by using algebra properties and trigonometric formulas, including the fundamental trigonometric formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:

$\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ Given.

$\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}$ Subtraction between fractions with different denominator / (- 1) · a = - a.

$\frac{2\cdot \sin x}{\cos^{2}x}$ Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)

$\frac{2\cdot \tan x}{\cos x}$ Definition of tangent / Result

By using algebra properties and trigonometric formulas we conclude that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equal to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ . Hence, the former expression is equivalent to the latter one.

To learn more on trigonometric equations: brainly.com/question/10083069

#SPJ1

4 0

2 years ago

-12=3(w-8)+3w what is w

ser-zykov [4K]

Answer:

$w=2$