SOMEONE PLEASE HELP FOR A KISS

Please help!!!!!!!!!!!!!

aivan3 [116]

Answers:

A
C
D

Step-by-step explanation:

We must simplify each option to see if they are equivalent to $-\frac{3}{8}$ .

Lets try A.

$-\frac{6}{16}$ can be simplified to $-\frac{3}{8}$ by dividing both the numerator and denominator by 3.

$-\frac{6}{16}$ ÷ $\frac{3}{3} = -\frac{3}{8}$

A is correct!

Lets try B

$\frac{12}{32}$ simplifies to $\frac{3}{8}$ . However, because this answer is not negative, it is not equivalent.

Lets try C

There is a negative in the numerator, making this fraction negative. So yes, $\frac{-3}{8} = -\frac{3}{8}$ .

Bonus Info: If there was a negative in both the numerator and denominator, the two negatives would cancel eachother out, making the fraction positive

C is correct!

Lastly, Lets try D

There is a negative in the denominator, so this fraction is negative. $\frac{9}{-24}$ can be simplified by dividing by 3 to $-\frac{3}{8}$ .

$\frac{9}{-24}$ ÷3 = $-\frac{3}{8}$

D is correct!

Hope this helped you!~

6 0

3 years ago

Please help me answer this.

inna [77]

Answer:

D. 4,-1

Step-by-step explanation:

The mathmatical way to solev it is to find the linear equation and plug in the points, but i just looked at the graph to see which point was in the shaded region.

5 0

2 years ago

The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).

natita [175]

Answer:

68% of jazz CDs play between 45 and 59 minutes.

Step-by-step explanation:

The correct question is: The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).

According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?

Let X = playing time of jazz CDs

SO, X ~ Normal( $\mu=52, \sigma^{2} =7$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, according to the 68-95-99.7 rule, it is stated that;

68% of the data values lie within one standard deviation points from the mean.

95% of the data values lie within two standard deviation points from the mean.

99.7% of the data values lie within three standard deviation points from the mean.

Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;

For 45 minutes, z-score is = $\frac{45-52}{7}$ = -1

For 59 minutes, z-score is = $\frac{59-52}{7}$ = 1

This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.

6 0

3 years ago

I need this two questions

Setler79 [48]

Just solve.

$(17-k)^3\\k=12 \\ \\ (17-12)^3 \\ \\ (5)^3 \\ \\ 125\\$

$\\\\(5+2n)^5 \\ n=-2 \\ \\ (5+2(-2))^5 \\ \\ (5-4)^5 \\ \\ (1)^5 \\ \\ 1$

4 0

3 years ago

Barry got a samll sandwich for lunch and ate 1/2 of his sandwich. Jonah got a large sandwich and ate 1/2 of his sandwich. Did Jo

xeze [42]

No, they did not eat the same amount. Barry ate less because his sandwich was smaller, so there would be a smaller half. Jonah ate more because his sandwich was bigger, so he would have eaten a bigger half.

8 0

3 years ago