Question

The figure below shows a triangular piece of cloth: Triangle ABC has angle ABC equal to 90 degrees and angle BAC equal to 32 degrees. Length of AC is 6 inches. What is the length of the portion BC of the cloth? 6 cos 32° 6 sin 32° cos 32 degrees divided by 6 sin 32 degrees divided by 6

Answer 1

Answer:

$6\ sin32^\circ$ is the length of portion BC.

Step-by-step explanation:

Please refer to the image attached.

$\angle ABC = 90 ^\circ\\\angle BAC = 32 ^\circ$

Length of portion AC = 6 inches.

As per trigonometric rules, we know that value of Sine function is as follows:

$sin\theta = \dfrac{\text{Perpendicular}}{\text{Hypotenuse}}$

Here, let $\theta = \angle BAC = 32 ^\circ$

So, perpendicular will be the side which is opposite to the $\angle BAC$.

Hence, side BC will be the perpendicular.

Using above formula:

$sin32^\circ = \dfrac{\text{BC}}{\text{AC}}$

$\Rightarrow BC = AC \times sin32^\circ\\\Rightarrow BC = 6 \times sin32^\circ$

Hence, Side BC is $6 \times sin32^\circ$

Answer 2

Answer:

6 sin 32 degrees

Step-by-step explanation:

i took the test