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rusak2 [61]
3 years ago
11

A rigid transformation can also be referred to as an isometric transformation. The prefix "iso-" means "of the same" and "-metri

c" means "measure." How does the meaning of the word isometric relate to determining if an isometric transformation occurred?
Mathematics
2 answers:
Svetllana [295]3 years ago
8 0
As stated by the statement, isometric means same measure. So, when a rigid transformation occurs all the measures of the original figure (which will be transformed) will be the same of the new figure (the result of the transformation).


That means that you can verify that the transformation used was rigid by checking the measures of both (original and transformed) figures: if and only if the meausures of the final figure are the same of the original figure the transformation was rigid.
Tcecarenko [31]3 years ago
3 0

Answer:

An isometric transformation creates an image that is congruent to the pre-image. All corresponding line segments and angle measures are equal.

Step-by-step explanation:

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To find K, we must use the fact that
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3 0
3 years ago
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Let C be the positively oriented square with vertices (0,0), (1,0), (1,1), (0,1). Use Green's Theorem to evaluate the line integ
liq [111]

Answer:

1/2

Step-by-step explanation:

The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that

\int\limits_C {L(x,y)} \, dx + {M(x,y)} \, dy = \int\limits^1_0\int\limits^1_0 {(Mx - Ly)} \, dxdy

Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.

  • Mx(x,y) = d/dx 8x²y = 16xy
  • Ly(x,y) = d/dy 7y²x = 14xy

Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral

\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy

We can compute the double integral by applying the Barrow's Rule, a primitive of 2xy under the variable x is x²y, thus the double integral can be computed as follows

\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy = \int\limits^1_0 {x^2y} |^1_0 \,dy = \int\limits^1_0 {y} \, dy = \frac{y^2}{2} \, |^1_0 = 1/2

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4 0
2 years ago
Daniela invested a total of $50,000, some in a certificate of deposit (CD) and the remainder in bonds. The amount invested in bo
LekaFEV [45]

Answer:

The amount invested in bonds = 35,000

The amount invested in CD = 15,000.

Step-by-step explanation:

The total amount that Daniela invested is $50,000, this means if we call the amount invested in bonds b, and the amount invested in CD d, then we have:

b+d=50,000 this says the total amount Daniela invested is $50,000.

And since the amount invested in bonds b is $5,000 more than twice the amount Daniela put into the CD, we have:

b=5,000+2d.

Thus, we have two equations and two unknowns b and d:

(1). b+d=50,000

(2). b=5,000+2d,

and we solve this system by substituting b from the second equation into the first:

b+d=50,000\\5,000+2d+d=50,000\\3d=45,000\\\\\boxed{d=15,000}

or, the amount invested in CD is $15,000.

With the value of d in hand, we now solve for b from equation(2):

b=5,000+2d\\b=5000+2(15,000)\\\boxed{b=35,000}

or, the amount invested in bonds is $35,000.

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Answer:

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