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Komok [63]
3 years ago
6

2 x 10 to the 3rd power standard form

Mathematics
1 answer:
cricket20 [7]3 years ago
5 0
2 x 10 to the 3rd power is
2x10^3
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What is the area of this figure?
Oksanka [162]
<h3>Answer:  297 square cm</h3>

=============================================

Work Shown:

Break up the figure as shown in the diagram below.

A rectangle and trapezoid form

-------------

Area of rectangle = base*height = 9*15 = 135 cm^2

Area of trapezoid = (1/2)*(b1+b2)*h = (1/2)*(18+9)*12 = 162 cm^2

total area = (area of rectangle)+(area of trapezoid)

total area = (135) + (162)

total area = 297 square cm

3 0
3 years ago
Select the correct name for the following line.
gavmur [86]
Line AB is a line, for the line continues through the points given and goes on 'forever'

hope this helps
3 0
3 years ago
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For a craft project, two equilateral triangles are taped together to create a quadrilateral.
Anika [276]
If these are the missing parts: 

What is the quadrilateral?

a.rhombus
b. rectangle
c. trapezoid
<span>d. square

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Rhombus has equal sides but its is different from a square because it looks like a diamond. 
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3 0
3 years ago
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Is the relationship shown by the data linear? If so, model the data with an equation. x= -7, -5, -3 ,-1 , y = 5, 9, 13, 17
PIT_PIT [208]
First we take the two points (-7,5) and (-5,9).
Compute the slope: \frac{9-5}{-5+7}=2
Then the linear relation may be in the following form y=2x+b
Since the point (-7,5) is on the line, then 5=-7(2)+b\text{ then }b=19.
The relation is then y=2x+19.
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3 0
3 years ago
What is the 6th term of the geometric sequence where a1 = 1,024 and a4 = −16? 1 −0.25 −1 0.25
VLD [36.1K]

The n-th term is given by

a_n=a_1\cdot r^{(n-1)}\qquad\text{where r is the common ratio}

Then we can find the common ratio from the given terms.

\dfrac{a_4}{a_1}=\dfrac{a_1\cdot r^{(4-1)}}{a_1}=r^3=\dfrac{-16}{1024}=\left(\dfrac{-1}{4}\right)^3\\\\r=\dfrac{-1}{4}\\\\a_6=1024\left(\dfrac{-1}{4}\right)^5=-1

The appropriate choice is -1.

8 0
4 years ago
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