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3 years ago

Find the value of x if the two triangles are similar. Explain.

Mathematics

1 answer:

Bas_tet [7]3 years ago

8 0

Answer:

Step-by-step explanation: Subtract the sum of the two angles from 180 degrees. The sum of all the angles of a triangle always equals 180 degrees. Write down the difference you found when subtracting the sum of the two angles from 180 degrees. This is the value of X.

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Maria handed out 125 flyers that gave students the time and locationtry outs for the school volleyball team. What is 125 written

Temka [501]

One way is to factor and see which ones repeat

125=5*5*5
it is 5 times itself 3 times
5^3

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2 years ago

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What is the formula of a²-b²?

Thepotemich [5.8K]

Answer:

The formula of a²-b² are as follows:

Step-by-step explanation:

(a-b)(a+b)

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3 years ago

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Harlon wrote the equation uppercase A = 18 (x squared + 1) to find the area of a rectangle that has a length of x squared + 1 an

Arturiano [62]

Answer:

its A

Step-by-step explanation:

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3 years ago

What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? (5 points) y = 4x − 2 y = 2x − 4 y = −3(

DIA [1.3K]

For this case we have that by definition, the point-slope equation of a line is given by:

$y-y_ {0} = m (x-x_ {0})$

We have the following points:

$(x_ {1}, y_ {1}) :( 2,6)\\(x_ {2}, y_ {2}) :( 4,0)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0-6} {4-2} = \frac {-6} {2} = -3$

We chose a point:

$(x_ {0}, y_ {0}) :( 4,0)$

Substituting in the equation we have:

$y-0 = -3 (x-4)\\y = -3 (x-4)$

Finally, the equation is: $y = -3 (x-4)$

Answer:

OPTION C

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3 years ago

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What’s the circumference, to this problem ?

Dafna11 [192]

Answer:

The formula to get the circumference of a circle is $C=2*\pi * r$ but in this case we see that a diameter is being used therefore we can get rid of the 2 and the r because that is what the diameter and just replace d into there like this $C=d*\pi$ .

We can then input the value and we get that $C=1*\pi$ which then just narrows down to $C=3.142$ .

<u><em>Hope this helps! Let me know if you have any questions</em></u>

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2 years ago