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Sedaia [141]
2 years ago
15

Find the inner product for (7,1) (0 -2) and state whether the vectors are perpendicular.

Mathematics
1 answer:
Fofino [41]2 years ago
6 0

Answer:

the answer is 67.980

Step-by-step explanation:

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Which choices are real numbers? Check all that apply.
Nonamiya [84]

Answer:

Step-by-step explanation:

Exponents with fractions in them are really just radical notation in a different form. You've probably seen the square root sign.

That can be written as 

x^(1/2)

...and when you take an even root of a negative number, there is no real answer. (2 is an even number).

Looking at the answer choices here, we can see that B and D use even roots, so they will give non-real answers.

So, A and C are the answer choices to select.

5 0
3 years ago
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Evaluate 1/4c + 3d when c = 6 and d = 7
maxonik [38]

Answer:

22 1/2

Step-by-step explanation:

1/4×6=1 1/2

3×7=21

21+1 1/2=22 1/2

7 0
2 years ago
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I’ll make brainlest. help asap pls
Liono4ka [1.6K]

Answer:

(2, -1)

Step-by-step explanation:

We can add the first equation by the second

(4x + 6y = 2)+(-4x + 4y = -12)=

10y=-10

we divide both sides by 10 to get

y=-1

We plug -1 in the second equation to get:

-4x+4(-1)=-12

-4x-4=-12

-4x=-8

Now, we divide both sides by -4

x=2

Hope this helps!

6 0
2 years ago
Bruce pitches for his little brother's baseball team. He has observed that the number of pitches a batter hits varies and is giv
liberstina [14]
Hello!

If Bruce observes that the number of pitches a batter hits varies and is given by the function f(x)=x-11, and the batters get {4, 12, 14, 27, 42}, then Bruce threw {15, 23, 25, 38, 53} pitches. We get this solution set by adding 11 to each element in the set {4, 12, 14, 27, 42}. 
Have a nice day
6 0
3 years ago
Occasionally a savings account may actually pay interest compounded continuously. For each deposit, find the interest earned if
Ugo [173]

1. Occasionally a savings account may actually pay interest compounded continuously. For each​ deposit, find the interest earned if interest is compounded​ (a) semiannually,​ (b) quarterly,​ (c) monthly,​ (d) daily, and​ (e) continuously. Use 1 year = 365 days.

Principal ​$1031

Rate 1.4%

Time 3 years

Answer:

a) $ 44.07

b) $ 44.15

c) $ 44.20

d) $ 44.22

e) $ 44.22

Step-by-step explanation:

The formula to find the total amount earned using compound interest is given as:

A = P(1 + r/n)^nt

Where A = Total amount earned after time t

P = Principal = $1031

r = Interest rate = 1.4%

n = compounding frequency

t = Time in years = 3 years

For each​ deposit, find the interest earned if interest is compounded

(a) semiannually

This means the interest is compounded 2 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/2) ^2 × 3

A = 1031 (1 + 0.007)^6

A = $ 1,075.07

A = P + I where

I = A - P

I = $1075.07 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.07

​(b) quarterly

This means the interest is compounded 4 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/4) ^4 × 3

A = 1031 (1 + 0.014/4)^12

A = $ 1,075.15

I = A - P

I = $1075.15 - $1031

A = P + I where

P (principal) = $ 1,031.00

I (interest) = $ 44.15

(c) monthly,

​ This means the interest is compounded 12 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/12) ^12 × 3

A = 1031 (1 + 0.014/12)^36

A = $ 1,075.20

A = P + I where

I = A - P

I = $1075.20 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.20

(d) daily,Use 1 year = 365 days

This means the interest is compounded 365 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/365) ^2 × 3

A = 1031 (1 + 0.00365)^365 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

(e) continuously. .

This means the interest is compounded 2 times in a year

Hence:

A = Pe^rt

A = 1031 × e ^0.014 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

5 0
2 years ago
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