Ask question

Ask question

All categories

3 years ago

15

The lock is numbered from 0 to 49. Each combination uses three numbers in a right, left, right pattern. Find the total number of

possible combinations for the lock

1 answer:

vekshin13 years ago

5 0

The answer is 79507
49 times 49 times 49

You might be interested in

3/4% of 170 Please write helpful answer

telo118 [61]

Answer:

1.275

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Help, and please show your work.

VLD [36.1K]

Answer:

for #9:

tan 30=x/10

tan 30*10=x

x=5.77=5.8

for #10:

tan 40=4/x

x*tan 40=4

x=4/tan 40

x=4.76=4.8

Step-by-step explanation:

hope all that helped lol

7 0

3 years ago

Read 2 more answers

Consider the following pair of equations:

Aloiza [94]

Y = 3x + 3 this is equation 1
y = x -1 this is equation 2
since equation 1 and 2 already defined y in terms of x, we're just gonna substitute y into the other equation. as 2 is shorter I'm going with that today
x - 1 = 3x +3
-1 - 3 = 3x - x
-4 = 2x
x = -2
now we've got x just sub it in equation 2
y = -2 -1
y = -3
so the answer is (-2,-3)

5 0

3 years ago

Urgent! Please refer to photo below for full question.

yuradex [85]

Answer:

A. The real part of the complex number is: A:3

B. The imaginary part of the complex number is: B:2i

Step-by-step explanation:

6 0

4 years ago

the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width

dolphi86 [110]

Answer:

Length = 17 inches

Width = 12 inches

⠀

Step-by-step explanation:

⠀

As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

⠀

Now, <u>According to the Question :</u>

⠀

${\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}$

⠀

${\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}$

⠀

${\longrightarrow \qquad { {\sf{2 ( 2x + 5 )= 58 }}}}$

⠀

${\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}$

⠀

${\longrightarrow \qquad { {\sf{ 4x = 58 - 10}}}}$

⠀

${\longrightarrow \qquad { {\sf{ 4x = 48}}}}$

⠀

${\longrightarrow \qquad { {\sf{ x = \dfrac{48}{4} }}}}$

⠀

${\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\: \: \bigstar$

⠀

Therefore,

The width of the rectangle is 12 inches .

⠀

Now, We are to find the length of the rectangle:

${\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}$

⠀

${\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}$

⠀

${\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}$

⠀

Therefore,

The length of the rectangle is 17 inches .

⠀

8 0

2 years ago

Read 2 more answers