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Serga [27]
3 years ago
15

The lock is numbered from 0 to 49. Each combination uses three numbers in a right, left, right pattern. Find the total number of

possible combinations for the lock
Mathematics
1 answer:
vekshin13 years ago
5 0
The answer is 79507
49 times 49 times 49
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Find the diameter of a cone that has a volume of 104.67 cubic inches and a height of 4 inches. Use 3.14 for pi. 4 inches 6 inche
aleksandr82 [10.1K]
V:  volume of a cone = (πr²h)/3 = 104.67 in³
π:  pi = 3.14
r:  radius = 1/2 diameter = [unknown]
h:  height = 4 in

V = (πr²h)/3
V = r²(πh)/3

r² = (3V)/(πh)
r² = (3 ×104.67)/(3.14 × 4)
r² = 25

r = √25
r = 5  (but remember the radius is only 1/2 the diameter)

thus . . . 

<u><em>d = 10 in </em></u>
8 0
3 years ago
Read 2 more answers
Christian wants to make an A in his class. There are 5 exams this year, and he has taken 4 of them. His grades were 84, 88, 95,
ioda

Answer:

last test grade=x     x ≥ 79 so 79%

Step-by-step explanation:

(84/5)+(88/5)+(95/5)+(104/5)+(x/5) ≥ 90

Simplify: (371/5)+(x/5) ≥ 90

Subtract (371/5) from both sides

Then you have (x/5) ≥ (79/5)

Then multiply both sides by 5 and you have x ≥ 79

P.S. If it was helpful please consider giving me brainliest. =)

3 0
3 years ago
Complete the equation of variation where y varies inversely as x and y = 0.125 when x = 8.
patriot [66]
Complete the equation of variation where y varies inversely as x and y = 0.125
when x=8

3 0
3 years ago
How do you evaluate 3ab
dimaraw [331]
Lets say a=2 and b=5  you now plug in you numbers to get 3x2x5 we know 3x2=6 so now take 6 and multiply it by 5 so 6x5=30  you can also set this equal to 0 3ab=0 then divide by either a or b ill show you both if you divide by a you are left with 3b=a if you divide by b than you get 3a=b
5 0
3 years ago
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln(x), [1, 5]
matrenka [14]

Answer:

Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]

Step-by-step explanation:

We are given that a function

f(x)=ln(x)

Interval [1,5]

The given function is defined on this interval.

Hypothesis of Mean Value Theorem:

(1) Function is continuous on interval [a,b]

(2)Function is defined on interval (a,b)

From the graph we can see that

The function is continuous on [1,5] and differentiable at(1,5).

Hence, the function satisfies the hypothesis of the Mean Value Theorem.

5 0
3 years ago
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