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iris [78.8K]
3 years ago
6

Consider the following pair of equations:

Mathematics
1 answer:
Aloiza [94]3 years ago
5 0
Y = 3x + 3 this is equation 1
y = x -1 this is equation 2
since equation 1 and 2 already defined y in terms of x, we're just gonna substitute y into the other equation. as 2 is shorter I'm going with that today
x - 1 = 3x +3
-1 - 3 = 3x - x
-4 = 2x
x = -2
now we've got x just sub it in equation 2
y = -2 -1
y = -3
so the answer is (-2,-3)

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F(x + 1) = 3x - 7<br> f(x) = ?<br> Cevabi kitabda=3x-10<br> Nasil yapmiş kitabda
lina2011 [118]

Answer:

<h2>f(x) = 3x + 4</h2>

Step-by-step explanation:

f(x + 1) = 3x - 7

f(x) = f(x + 1 - 1) = 3(x - 1) + 7 = 3x - 3 + 7 = 3x + 4

Check

f(x) = 3x + 4

f(x + 1) = 3(x + 1) + 4 = 3x + 3 + 4 = 3x + 7 CORRECT

8 0
3 years ago
What happens when the ordered pair (x,y) moves to the right?
UNO [17]
Question is unclear
4 0
3 years ago
Solve 2 1/2 divided by 5 1/3 = 8/x
ipn [44]
2\frac { 1 }{ 2 } \quad divided\quad by\quad 5\frac { 1 }{ 3 } \\ \\ 2\frac { 1 }{ 2 } =2+\frac { 1 }{ 2 } =\frac { 5 }{ 2 } \\ \\ 5\frac { 1 }{ 3 } =5+\frac { 1 }{ 3 } =\frac { 15+1 }{ 3 } =\frac { 16 }{ 3 } \\ \\ \\ \frac { \frac { 5 }{ 2 }  }{ \frac { 16 }{ 3 }  }

We're dividing fractions, so we will flip the one in the denominator upside down and we will multiply it with the numerator.

\frac { \frac { 5 }{ 2 }  }{ \frac { 16 }{ 3 }  } \quad =\quad \frac { 5 }{ 2 } \cdot \frac { 3 }{ 16 } =\frac { 5\cdot 3 }{ 2\cdot 16 } =\frac { 15 }{ 32 }

Let's equal this too 8/x

\frac { 15 }{ 32 } =\frac { 8 }{ x }

Cross multiply. 

8\cdot 32=15\cdot x\\ \\ 256=15x

Divide both sides by 15.

\frac { 256 }{ 15 } =\frac { 15x }{ 15 } \\ \\ \frac { 256 }{ 15 } =x

4 0
3 years ago
What is the constant of variation of y=3x
bearhunter [10]
Y=kx so 3 would be the constant
4 0
3 years ago
What must be added to -31 to get 12
konstantin123 [22]

Answer:

43

Step-by-step explanation:

31+12=43

Therefore adding 43 to -31 should give the answer 12.

3 0
2 years ago
Read 2 more answers
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