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natita [175]
3 years ago
7

What is hydraulic fracturing?

Computers and Technology
1 answer:
777dan777 [17]3 years ago
4 0
The meaning of hydraulic fracturing is the process thats used 9 from 10 of natural gas wells in the U.S. where there are lots and millions of gallons of water, sand, chemicals and others that is pumped under the ground to divided and break apart the rocks which releases the gas.

hope this helped because i learned about this and i am sure :)
You might be interested in
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
andriy [413]

Binary values are used to denote the 'ON' and 'OFF' state of a computer. The 'ON' state is denoted by the binary value '1'

  • The 'ON' state of a computer represents the mode when the computer system is running and can be used to perform computing operations.

  • The binary values '0' and '1' are used to designate the ON and OFF state.

  • When the computer is ON, it is designated by the binary value 1 ; while the OFF state is designated by the binary value 0.

Therefore, the number which signifies the ON state of a computer is 1.

Learn more :brainly.com/question/4722254

4 0
2 years ago
a marketing company is setting up a new office in the city. which type of contract should they sign for periodic maintenance of
True [87]

Answer:

The contract they had to sign was a computer maintenance contract with computer service providers.

Explanation:

<em>Why </em><em>do companies have to </em><em>maintain computers</em><em> regularly? </em>

Because of all the activities of the company at this time on average use applications from computers. With the maintenance of computers, the activities of the company will continue to run well.

There are two types of maintenance that can be carried out:

  • Hardware Maintenance
  • Software Maintenance

#AnswerForTrees

8 0
2 years ago
Write a function called count_occurrences that takes two strings. The second string should only be one character long. The funct
iVinArrow [24]

Answer:

Here is the Python function:

def count_occurrences (string1 , string2):  # method that takes two strings as parameter and returns how many times second string occurs in first

   count = 0  #counts number of occurrence of string2 in string1

   for word in string1:  #iterates through each word of the string1

       for character in word:  #iterates through each character of each word in string1

           if character == string2:  # checks if the character in string1 is equal to the character of string2

               count = count + 1  #adds 1 to the count of string2 in string1

   return count  #returns number of times the string2 occurs in string1

#in order to check the working of the function add the following lines to the code:    

first_str = input("Enter the first string: ")  #prompts user to enter first string

second_str = input("Enter the second string (one character long): ") #prompts user to enter second string which should be one character long

occurrence = count_occurrences(first_str,second_str)  #calls count_occurrences method by passing both strings to it

print(second_str,"occurs",occurrence,"times in",first_str) #prints how many times the second_str occurs in the first_str on output screen

Explanation:

The program is well explained in the comments added to each statement of the above code. I will explain the program with an example:

Suppose

string1 = "hello world"

string2 = 'l'

So the method count_occurrences() should return how many times l occurs in hello world.

count is used to count the number of occurrences of l in hello world. It is initialized to 0.

The first loop iterates through each word of string1. The first word of string1 is "hello"

The second loop iterates through each character/letter of each word. So the first letter of "hello" word is 'h'.

The if condition if character == string2: checks if the character is equal to string2 i.e. l.

character = "h"

string2 = "l"

The are not equal so the program moves to the next character of word hello which is e. The if condition again evaluates to false because e is not equal to l. So the program moves to the next character of word hello which is l.

This time the if condition evaluates to true because

character = "l"

string2 = "l"

character == string2

l == l

So the if part is executed which has the following statement:

count = count + 1

So the count is added to 1. count was 0 previously. Now

count = 1

Next the program moves to the next character of word hello which is l. This time the if condition evaluates to true because the character l matches with string2. So count is again incremented to 1. count = 2.

Next the program moves to the next character of word hello which is o. The if condition evaluates to false as o does not match with string2 i.e. l. So the count remains 2.

Next the first loop moves to the next word of the string1 = "world". The inner (second) for loop iterates through each character of "world" from "w" to "d" and checks if any character is equal to string2. Only one character is equal to string2 in "world". So count is incremented to 1. Hence count = 3

After the loop ends the statement return count returns the number of times string2 occurs in the string1. So the output is:

l occurs 3 times in hello world  

8 0
3 years ago
A large population of ALOHA users manages to generate 50 requests/sec, including both originals and retransmissions. Time is slo
krok68 [10]

Answer:

The answer is below

Explanation:

Given that:

Frame transmission time (X) = 40 ms

Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request

a) Probability that there is success on the first attempt = e^{-G}G^k but k = 0, therefore Probability that there is success on the first attempt = e^{-G}=e^{-2}=0.135

b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)

P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = [1-e^{-G}]^k=[1-0.135]^k=0.865^k

P(success in k+1 attempt) = e^{-G}=e^{-2}=0.135

Probability of exactly k collisions and then a success = 0.865^k0.135

c) Expected number of transmission attempts needed = probability of success in k transmission = e^{G}=e^{2}=7.389

6 0
3 years ago
The columns of a spreadsheet data source are A. form letters. B. the mailing list. C. data points. D. fields.
mojhsa [17]

I believe it is C, I'm so sorry if im incorrect.

8 0
3 years ago
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