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irina1246 [14]
3 years ago
13

An employee of a company gets a three-digit lock code to enter the building the digits could be 1, 5, or 7 identify the lock cod

es in the sample space that have at least two fives
a.) 155, 551, 555, 557, 755
b.) 155, 515, 551, 557, 575, 755
c.) 155, 515, 551, 557, 575, 755
d.) 115, 151, 155, 157, 175, 511, 515, 517, 551, 555, 557, 571, 575, 577, 715, 751, 755, 757, 775
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer:

a, b, c

Step-by-step explanation:

You might be interested in
-2n +15=n-60
RideAnS [48]

Answer:

n = 25

Step-by-step explanation:

-2n + 15 = n - 60

Subtract 15 to both sides

-2n = n - 75

Subtract n to both sides

-3n = -75

Divide -3 to both sides

n = 25

Best of Luck!

8 0
4 years ago
Read 2 more answers
A jet travels 2301 miles against the wind in 3 hours and 2811 miles with the wind in the same amount of time. What is the rate o
astraxan [27]

Answer:

The rate of the jet in still air is 852 miles per hour. The rate of the wind is 85 miles per hour.

Step-by-step explanation:

Let suppose that jet travels uniformly, that is, at constant speed, the expressions for its travels against the wind and with the wind are, respectively:

Against the wind

v -u = \frac{\Delta x_{1}}{\Delta t_{1}}

With the wind

v +u = \frac{\Delta x_{2}}{\Delta t_{2}}

Where:

v - Speed of the jet in still air, measured in miles per hour.

u - Speed of wind, measured in miles per hour.

\Delta x_{1}, \Delta x_{2} - Distances travelled by jet against the wind and with the wind, measured in miles.

\Delta t_{1}, \Delta t_{2} - Times against the wind and with the wind, measured in hours.

By adding both expressions:

2\cdot v = \frac{\Delta x_{1}}{\Delta t_{1}}+\frac{\Delta x_{2}}{\Delta t_{2}}

v = \frac{1}{2}\cdot \left(\frac{\Delta x_{1}}{\Delta t_{1}} + \frac{\Delta x_{2}}{\Delta t_{2}} \right)

Given that \Delta x_{1} = 2301\,mi, \Delta t_{1} = 3\,h, \Delta x_{2} = 2811\,mi and \Delta t_{2} = 3\,h, the speed of the jet is:

v = \frac{1}{2}\cdot \left(\frac{2301\,mi}{3\,h}+\frac{2811\,mi}{3\,h}  \right)

v = 852\,\frac{mi}{h}

The rate of the jet in still air is 852 miles per hour.

Lastly, the rate of the wind is:

u = \frac{\Delta x_{2}}{\Delta t_{2}}-v

u = \frac{2811\,mi}{3\,h}-852\,\frac{mi}{h}

u = 85\,\frac{mi}{h}

The rate of the wind is 85 miles per hour.

 

5 0
3 years ago
Allison earned $200 the first month she worked and $250 the second month she worked. By what percent did her salary increase?
Afina-wow [57]

Answer: 25%

Step-by-step explanation:

From the question, we are informed that Allison earned $200 the first month she worked and $250 the second month she worked.

The percentage increase in her salary will be calculated as:

= Salary Increase / Old salary × 100

= (250 - 200) / 200 × 100

= 50/200 × 100

= 1/4 × 100

= 25%

The percentage increase is 25%

3 0
3 years ago
34 = 10 + 4q<br> Solve<br> Need help
LiRa [457]

Simplifying

34 = 10 + 4q

Solving

34 = 10 + 4q

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-4q' to each side of the equation.

34 + -4q = 10 + 4q + -4q

Combine like terms: 4q + -4q = 0

34 + -4q = 10 + 0

34 + -4q = 10

Add '-34' to each side of the equation.

34 + -34 + -4q = 10 + -34

Combine like terms: 34 + -34 = 0

0 + -4q = 10 + -34

-4q = 10 + -34

Combine like terms: 10 + -34 = -24

-4q = -24

Divide each side by '-4'.

q = 6

Simplifying

q = 6

hope this helps please mark brainliest

6 0
3 years ago
The ratio of boys to girls in a class is 4:5 what fraction of teh class are boys
GalinKa [24]

Answer:

4/9

Step-by-step explanation:

If you add the ratios, it gives you the total, so 4 + 5 = 9.  9 total students.  Since boys is represented by 4, then 4/9 is the fraction for boys and 5/9 is the fraction for girls.

5 0
4 years ago
Read 2 more answers
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