K² + 13k + 30 = 0
This is a quadratic equation. Let's attempt solving it by factorization.
Coefficient of k² = 1, last term = 30
Multiply these two together 1*30 = 30
We think of two numbers that multiply to give 30 and add to give the middle term 13.
The two numbers are 3 and 10.
3*10 = 30, 3 + 10 = 13.
we replace the 13k with 3k + 10k
k² + 13k + 30 = 0
k² + 3k + 10k + 30 = 0
k(k + 3) + 10(k + 3) = 0
(k + 3)(k + 10) = 0
(k + 3) = 0 or (k + 10) = 0
k = 0 - 3 or k = 0 - 10
k = -3, or -10
I hope this helps.
Answer:
The fourth opition!
Step-by-step explanation:
180-2(72)=x. The reason being it says TWO angels of 72 and if you times that by two and subtract by 180 youll get the missing angle!!
What is your problem you are having?
Answer:
option C
Step-by-step explanation:
to find the solution for the equation 4x + 2 = x + 3, graph the equations
y= 4x+2 and y=x+3
Lets make a table for each equation
x y= 4x+2
-1 4(-1) + 2= -4+2 = -2
0 4(0) + 2= 2
1 4(1) + 2= 6
plot all the points on graph
Lets make table for second equation
x y= x+3
-1 -1+3 = 2
0 0+3 = 3
1 1+3 = 4
Plot the point on the graph and make a line
option C is correct
Answer:
your answer will be option d
Step-by-step explanation:
because cosine =base/hypotenus
and here 8/17
hope ur help
