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svlad2 [7]
2 years ago
13

WILL GIVE BRAINLIEST AND 20 POINTS

Mathematics
2 answers:
monitta2 years ago
7 0

Answer:

The answer would be 180-2(72)= x

Step-by-step explanation:

This will end up being

180 - 144 = 36

Hope I could help!!

If I was correct, I would really appreciate it if you mark me as brainliest!

Pachacha [2.7K]2 years ago
4 0

Answer:

The fourth opition!

Step-by-step explanation:

180-2(72)=x. The reason being it says TWO angels of 72 and if you times that by two and subtract by 180 youll get the missing angle!!

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Someone help plz, I'm stuck
VladimirAG [237]

Answer:

Original price reduced by 30%

Step-by-step explanation:

You want the deepest discount, which means you want the greatest percent/amount off. The first choice is 20%. The second is 30%. The third one is 25%, because you are paying for 75% (100-75). The second choice offers the deepest discount because it is 30% off.

6 0
3 years ago
Choose the problem modeled by the picture. A) 1 3 × 3 2 = 3 6 B) 1 4 × 3 6 = 3 24 C) 3 4 × 1 6 = 3 24 D) 1 3 × 3 4 = 3 12
Morgarella [4.7K]

Answer:  The answer is (C) 3 4 × 1 6 = 3 24


Step-by-step explanation:  We are given a rectangular picture made of square boxes and we are to find among the given options which is modelled by the given picture.

In the diagram, there are 6 boxes lengthwise and 4 boxes breadthwise. Also, 3 × 4 boxes are painted yellow and 1 × 6 boxes are painted blue. The common boxes will be 3.

Therefore, the correct choice is  3 4 × 1 6 = 3 24

Hence, (C) is the correct option.



3 0
3 years ago
Read 2 more answers
What is the value of x?
defon

Answer:

X=35

Step-by-step explanation:

6X =45 SO ANSWER TO THE QUESTION IS 35

5 0
3 years ago
A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min
Dmitry [639]

At any time t (min), the volume of solution in the tank is

500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}

If A(t) is the amount of salt in the tank at any time t, then the solution has a concentration of \dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}.

The net rate of change of the amount of salt in the solution, A'(t), is the difference between the amount flowing in and the amount getting pumped out:

A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)

Dropping the units and simplifying, we get the linear ODE

A'=10+5\sin\dfrac t4-\dfrac A{10}

10A'+A=100+50\sin\dfrac t4

Multiplying both sides by e^{10t} allows us to identify the left side as a derivative of a product:

10e^{10t}A'+e^{10t}A=\left(100+50\sin\dfrac t4\right)e^{10t}

\left(e^{10}tA\right)'=\left(100+50\sin\dfrac t4\right)e^{10t}

e^{10t}A=\displaystyle\int\left(100+50\sin\dfrac t4\right)e^{10t}\,\mathrm dt

Integrate and divide both sides by e^{10t} to get

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+Ce^{-10t}

The tanks starts off with 30 lb of salt, so A(0)=30 and we can solve for C to get a particular solution of

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+\dfrac{32,220}{1601}e^{-10t}

6 0
3 years ago
Solve the power equation <br> x to the 1/2 power + 3=5
sp2606 [1]

Answer:

x = 4

Step-by-step explanation:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

6 0
3 years ago
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