The watch repairman needs to replace the battery on some watches he has 43 minutes before closing how many batteries can he repl
1 answer:
Answer:
5 batteries with a leftover time of 3 minutes
Step-by-step explanation:
If it takes the watch repairman 8 minutes to replace a battery on the watches
In 43 minutes, he will be able to replace batteries on the watches
=
Therefore the watch repairman can replace 5 watch batteries.
He will have 3 minutes left over.
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Answer:
c
Step-by-step explanation:
Here's how this works:
Get everything together into one fraction by finding the LCD and doing the math. The LCD is sin(x) cos(x). Multiplying that in to each term looks like this:
In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:
Put everything over the common denominator now:
Since , we will make that substitution:
We could separate that fraction into 2:
×
and
Therefore, the simplification is
sec(x)csc(x)