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3 years ago

Andria wrote the following statements:

1 answer:

6 0

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The geometry term does each statement above represents is Statement 1 is postulate because you have to prove that corresponding angles are congruent.

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The sale price of every item in a store is 85% of its usual price.

IgorC [24]

Answer:

$25.5

Step-by-step explanation:

To find 85% of $30, we can simply multiply the usual price, $30, by the decimal form of the percentage.

The decimal form of 85% is .85.

Now, multiply.

30*.85=25.5

The sale price of the backpack is $25.5.

Hope this helps!

3 0

3 years ago

7. Which of the following can be determined from the graph below?

tatyana61 [14]

Answer:

The ordered pair (6,25) is a solution to both

$y=-\frac{5}{2}x+40$ and $y=\frac{5}{3}x+15$

Step-by-step explanation:

Part 7)

step 1

Find the equation of the line with positive slope

take the points (0,15) and (9,30)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{30-15}{9-0}$

$m=\frac{15}{9}$

simplify

$m=\frac{5}{3}$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=\frac{5}{3}$

$b=15$

substitute

$y=\frac{5}{3}x+15$

step 2

Find the equation of the line with negative slope

take the points (0,40) and (8,20)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given values

$m=\frac{20-40}{8-0}$

$m=-\frac{20}{8}$

simplify

$m=-\frac{5}{2}$

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=-\frac{5}{2}$

$b=40$

substitute

$y=-\frac{5}{2}x+40$

step 3

Find the solution of the system

we know that

The solution of the system of equations is the intersection point both graphs

The intersection point is (6,25) ----> see the graph

therefore

The ordered pair (6,25) is a solution to both $y=-\frac{5}{2}x+40$ and

$y=\frac{5}{3}x+15$

7 0

3 years ago

Three friends fill bags with trash at a neighborhood cleanup. Randall's bag weighs

BabaBlast [244]

Answer:

Randall picks up 68 pounds

Seth picks up 40 pounds

Joanna picks up 52 pounds

Step-by-step explanation:

Let us make an equation in x to find it

∵ Randall's bag weighs 3x - 7 pounds

∵ Joanna's bag weighs 2x + 2 pounds

∵ Seth's bag weighs 2x - 10 pounds

∵ Randall's and Joanna's bags weigh 3 times as much as Seth's bag

- That means add Randall's bag and Joanna's bag and equate

the sum by 3 times Seth's bag

∵ Randall's bag + Joanna's bag = 3(Seth's bag)

∴ (3x - 7) + (2x + 2) = 3(2x - 10)

- Simplify the two sides

∴ (3x + 2x) + (-7 + 2) = 3(2x) - 3(10)

∴ 5x + (-5) = 6x - 30

∴ 5x - 5 = 6x - 30

- Add 5 to both sides

∴ 5x = 6x - 25

- Subtract 6x from both sides

∴ -x = -25

- Divide both sides by -1

∴ x = 25

Substitute x by 25 in the weight of each bag

∵ Randall's bag weighs = 3(25) - 7 = 75 - 7

∴ Randall's bag weighs = 68 pounds

∵ Seth's bag weighs = 2(25) - 10 = 50 - 10

∴ Seth's bag weighs = 40 pounds

∵ Joanna's bag weighs = 2(25) + 2 = 50 + 2

∴ Joanna's bag weighs = 52 pounds

7 0

3 years ago

Read 2 more answers

What do u have 2 do to solve

Nastasia [14]

5x^2 + 6x +13.88 is what is is simplified hope it helped a bit

8 0

3 years ago

Read 2 more answers

M is the midpoint of AN, A has coordinates

maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

Figure :-

$\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$} \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}$

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

$\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}$

On using this formula ,

$=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}$

8 0

3 years ago

Read 2 more answers