The sum clearly diverges. This is indisputable. The point of the claim above, that

is to demonstrate that a sum of infinitely many terms can be manipulated in a variety of ways to end up with a contradictory result. It's an artifact of trying to do computations with an infinite number of terms.
The mathematician Srinivasa Ramanujan famously demonstrated the above as follows: Suppose the series converges to some constant, call it

. Then

Now, recall the geometric power series

which holds for any

. It has derivative

Taking

, we end up with

and so

But as mentioned above, neither power series converges unless

. What Ramanujan did was to consider the sum

as a limit of the power series evaluated at

:

then arrived at the conclusion that

.
But again, let's emphasize that this result is patently wrong, and only serves to demonstrate that one can't manipulate a sum of infinitely many terms like one would a sum of a finite number of terms.
Answer:
W = 21.44*10⁶J
Step-by-step explanation:
Given
y = x² (0 < x < 4)
γ = 10000 N/m³
W = ?
If we apply
y = 4² = 16 = h
y = x² ⇒ x = √y
then
V = π*(√y)²*dy = π*y*dy
W = (γ*V) *(16-y) = γ*π*y*dy*(16-y)
⇒ W = γ*π*∫y*(16-y)dy = γ*π*(8y²-(y³/3))
finally we obtain (0 < y < 16)
W = γ*π*(8y²-(y³/3)) = 10000*π*(8*16²-(16³/3)) = 21.44*10⁶J
Answer:
b=k3+24k2−3700k
r=(k3−5k2+3k−5)((−k)(4))
87(|k+1|)+2088
Step-by-step explanation:
Answer:

Step-by-step explanation:
1) Convert
to improper fraction. Use this rule:
.

2) Simplify 4 * 3 to 12.

3) Simplify 12 + 1 to 13.

4) Convert
to improper fraction. Use this rule:
.

5) Simplify 1 * 3 to 3.

6) Simplify 3 + 2 to 5.

7) Join the denominators.

8) Simplify.

9) Convert to mixed fraction.

(Decimal Form: 2.666667)
Thank you,
Eddie