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mafiozo [28]
3 years ago
12

What is( 5×100)+(6x10)+(8×1/10)+(9×1/1,000) in standard form

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

6x^10+2504/5+(9*1/1,0)

Step-by-step explanation:

Hope this helps :)

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Solve 4x+y=8 x+y=5 Solving by elimination
Ulleksa [173]

Answer:

y=4,x=1

Step-by-step explanation:

4x+y=8

x+y=5

subtract equation 2 from equation 1

3x + 0=3

3x=3

divide both sides by 3

x=1

substitute for x=1 in equation 2

x+y=5

1+y=5

y=5-1(collecting like terms)

y=4

3 0
3 years ago
Read 2 more answers
The average age of 15 students is 16 years. If teacher’s age is included the average increases by 1. Find teacher’s age. (a) 30
Mrac [35]

Answer:

Age of teacher = 32 years

Step-by-step explanation:

Average age of 15 students = 16 years

Sum of age of 15 students = 16 * 15 = 240 years

Average of age 15 students and a teacher = 17 years

Sum of age  15 students and a teacher = 17 * 16 =  272 years

Age of teacher = 272 - 240 = 32 years

4 0
3 years ago
Read 2 more answers
Which group contains triangles that are all similar?
torisob [31]

Answer:

Triangles represented by option B are similar triangles.

Step-by-step explanation:

Please find the attachment.

We have been given 4 group of triangles and we are asked to find which group contains similar triangles.

A. We can see from our diagram that triangles provided in option A are not similar.

The first triangle is an isosceles right triangle as it has 2 angles each having measure 45 degrees. By angle sum property the measure of 3rd angle will be:

180^o-(45^o+45^o)=180^o-90^o=90^o

The second triangle is an equilateral triangle as all the sides equal to 7 units, so all angles will be equal to 60 degrees.

The 3rd triangle is an isosceles triangle as  it has 2 angles each having measure 53 degrees. By angle sum property the measure of 3rd angle will be:

180^o-(53^o+53^o)=180^o-106^o=74^o

We can see that none of the triangles have same angle measures, therefore, option A is not a correct choice.

B. The triangles provided in option B are similar triangles as each triangle have one right angle and they are sharing the same vertex.

Let us assume that the common vertex has x degrees angle, then by angle sum property the measure of 3rd angle in each triangle will be 180-90-x=90-x degrees. Therefore, the triangles provided in option B are similar triangles by AAA similarity theorem.

C. The triangles provided in option C are not similar triangles as we are not told that the given lines are parallel or not. In addition the bottom figure is a quadrilateral as it has 4 angles, Therefore, the given triangles are not similar triangles.

D. We can see that our given triangles have vertical angles, so their measure will be 32 degrees. Since the given side lengths are different, therefore, this group of triangles is not similar.

5 0
3 years ago
Read 2 more answers
A rectangle has an area of 221 square units. The width of the rectangle is 13 units. The length of the rectangle is 3x + 2. What
vodka [1.7K]
The length is 17 and x=5


13 times 3x+2 = 221 so solve by dividing 221 by 13= 17.
Now we know that 3x+2= 17 so 3x= 15
x=5 

8 0
3 years ago
The little Mexican restaurant sells only two kinds of beef burritos mucho beef sandwich Lucho beef last week the restaurant orde
Finger [1]

Answer:

Cost of a single Mucho beef burrito: \$5.5

Cost of a double Mucho beef burrito: \$6.5

Step-by-step explanation:

<h3> The exercise is: "The Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant sold 16 orders of the single Mucho variety and 22 orders of the double Mucho. If the restaurant sold $231 Worth of beef burritos last week and the single neutral kind cost $1 Less than the double Mucho, how much did each type of burrito cost?"</h3>

Let be "x" the the cost in dollars of a single Mucho beef burrito and "y" the cost in dollars of a double Mucho burrito.

Set a system of equations:

\left \{ {{16x+22y=231} \atop {x=y-1}} \right.

To solve this system you can apply the Substitution Method:

1. Substitute the second equation into the first equation and solve for "y":

16(y-1)+22y=231\\\\16y-16+22y=231\\\\38y=231+16\\\\y=\frac{247}{38}\\\\y=6.5

2. Substitute the value of "y" into the second equation and evaluate in order to find the value of "x":

x=6.5-1\\\\x=5.5

5 0
3 years ago
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