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mafiozo [28]
3 years ago
12

What is( 5×100)+(6x10)+(8×1/10)+(9×1/1,000) in standard form

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

6x^10+2504/5+(9*1/1,0)

Step-by-step explanation:

Hope this helps :)

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Solve: 1/5(10x-15) = 1/4(12x-8)
valkas [14]
1/5(10x−15)=1/4(12x−8)

1/5(10x−15)=1/4(12x−8)

Simplify:

(1/5)(10x)+(15)(−15)=(1/4)(12x)+(1/4)(−8)(Distribute)

2x+−3=3x+−2

2x−3=3x−2

Subtract 3x from both sides.

2x−3−3x=3x−2−3x

−x−3=−2

Add 3 to both sides.

−x−3+3=−2+3

−x=1

Divide both sides by -1.

−x/−1 = 1/−1

x=−1

8 0
3 years ago
A) Calculate the value of x.
choli [55]

Answer:

18

Step-by-step explanation:

3x + 2x = 90

5x = 90

5x/5 = 90/5

x = 18

6 0
2 years ago
What are the prime factors of 117?
garik1379 [7]
The answer is

3^2 times 13
3 0
2 years ago
Read 2 more answers
Can be used to compare changes from one period to another.
vlada-n [284]

Answer:

c) Percentages

Step-by-step explanation:

Percentages can be used to compare changes from one period to another.

In calculating a percentage change, either a percentage increase or percentage decrease, we must have both the new and old measurement of the specific quantity.

For example, let's find percentage increase of the number of students that joined a book club using the parameters below;

Original number of students = 32

New number of students = 36

We will calculate the increase using;

Increase = original \; number  -  new \; number

Substituting the values, we have;

Increase = 36 - 32 = 4

Percentage \; increase = \frac{increase}{original \; number} * 100

Percentage \; increase = \frac{4}{32} * 100

Percentage \; increase = 0.125 * 100

Percentage increase = 12.5%

Therefore, the number of students in the school club increased by 12.5%.

8 0
3 years ago
Someone please solve this ASAP and give answer as a square root
natima [27]
Given pyramid with a regular hexagonal base,
side length=6\sqrt{3} cm
Height = 4 cm

We need to find the area of the hexagonal base.  First step is to find the apothm,
a=side*(\sqrt{3}/2 
=6*3/2=9
So the area of each equilateral triangle making up the base
=base*apothem/2
=6\sqrt{3} *9/2
=27\sqrt{3}
The area of base = 6 area of each triangle
=6*27\sqrt{3}
=162\sqrt{3}

Volume of pyramid = area of base * height /3
=162\sqrt{3}*4/3
=216\sqrt{3}

8 0
3 years ago
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