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nlexa [21]
3 years ago
13

The team ran

Mathematics
2 answers:
Viefleur [7K]3 years ago
5 0

Answer:

The team ran 2 miles.

Step-by-step explanation:

juin [17]3 years ago
3 0

The team ran 2 miles.

Step-by-step explanation:

Step 1; The track is \frac{3}{4} miles long and the team ran 2\frac{2}{3} laps on it. To calculate the distance run we multiply the number of laps ran with the distance on each lap.

Distance run = Number of laps × Distance on each lap.

Step 2; We convert 2\frac{2}{3} from a mixed fraction into an improper fraction. To do this, we multiply the whole number with the denominator of the fraction and add with it the numerator of the same fraction whereas the denominator remains unchanged. To convert the fraction 2\frac{2}{3} = ((2 × 3) + 2) / 3 = \frac{8}{3}.

Distance run = Number of laps × Distance on each lap = \frac{8}{3} × \frac{3}{4} = \frac{8}{4} = 2 miles.

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Answer:

in math its the answer to two numbers that are multiplied

Step-by-step explanation:

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4 0
3 years ago
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3(x-4) = 2(-2x + 1)<br>this is confusing me​
nata0808 [166]

Answer:

x = 2

Step-by-step explanation:

<em>Distribute</em>

3 (−4) = 2 (−2+1)

3 − 12 = 2 (-2x +1)

<em>Distrubute again</em>

3x - 12 = -4x + 2

<em>Add twelve to both sides of the equation</em>

<em>Simpfly</em>

3x = -4x + 14

<em>Add 4x to both sides of the equation</em>

<em>simpfly</em>

7x = 14

<em>Divide both sides of the equation by the same term</em>

<em>Simpfly</em>

x = 2

5 0
2 years ago
Given that y= 12 cm and θ= 24 °, work out x rounded to 1 DP.<br><br> (not drawn to scale.)
padilas [110]

Answer:

\huge\boxed{\sf x = 5.3}

Step-by-step explanation:

<h3><u>Given:</u></h3>

y = 12 cm

θ = 24°

Using trigonometric ratio, tan.

\displaystyle \boxed{tan \theta = \frac{opposite}{adjacent} }\\\\tan \ 24 = \frac{x}{12} \\\\0.445 = \frac{x}{12} \\\\Multiply \ 12 \ to \ both \ sides\\\\0.445 \times 12 = x\\\\5.3 = x\\\\x = 5.3\\\\\rule[225]{225}{2}

5 0
2 years ago
What is the value of x?
Molodets [167]

Answer:

x = 4√5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Trigonometry</u>

  • Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Define</u>

We are given a right triangle. We can use Pythagorean Theorem.

a = 19

b = x

c = 21

<u>Step 2: Find </u><em><u>x</u></em>

  1. Substitute:                    19² + x² = 21²
  2. Isolate <em>x</em> term:               x² = 21² - 19²
  3. Evaluate:                       x² = 441 - 361
  4. Subtract:                       x² = 80
  5. Isolate <em>x</em>:                       x = √80
  6. Simplify:                        x = 4√5

And we have our final answer!

8 0
3 years ago
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
2 years ago
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