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leva [86]
3 years ago
7

Someone pelase help ASAPPPPPP

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Answer:

the first one

Step-by-step explanation:

Julli [10]3 years ago
3 0

Answer:what is the typical # of holes for the buttons in the jar

Step-by-step explanation: how many buttons? only one number satisfys this

Are there any square buttons? Only one answer satisfys this (yes or no)

What is the typical(average) number of holes for the buttons in the jar? A statistical question will have an average of the whole

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the ratio of students with bikes to students with scooters in the school is 85:51. What is the greatest common factor that you c
Vikentia [17]
Answer:GCF=17

To find the greatest common factor, or GCF, of the numbers, we first need to list the prime factors of both 85 and 51

52=3*17

85=5*17

17 is the sole common factor that these two numbers have in common, therefore 17 is the GCF.

To simplify the ratio, simply divide both numbers by 17.

85:51 becomes 5:3
5 0
3 years ago
Read 2 more answers
Pls help if pls do most important 15 number 20 number 26 number 28 number 30 number 17 number 25 number 22 number 24 number if u
Tamiku [17]

Answer:

Step-by-step explanation:

15. \frac{cotx+1}{cotx-1} = \frac{cotx+cotx.tanx}{cotx-cotx.tanx} = \frac{cotx(1+tanx)}{cotx(1-tanx)} = \frac{1+tanx}{1-tanx}   \\

16.  \frac{1+cos\alpha }{sin\alpha } = \frac{sin\alpha }{1-cos\alpha }

=> (1+cos\alpha )(1-cos\alpha ) = sin^{2} \alpha \\=> 1-cos^{2}\alpha =sin^{2}  \alpha \\=> sin^{2}\alpha +cos^{2}\alpha =1\\

=> The clause is correct

17. Do the same (16)

18. \frac{sinx}{1-cosx}+\frac{sinx}{1+cosx} = \frac{sinx(1+cosx) + sinx(1-cosx)}{(1+cosx)(1-cosx)} = \frac{sinx + sinx.cosx + sinx - sinx.cosx}{1-cos^{2}x} = \frac{2sinx}{sin^{2}x }= \frac{2}{sinx} = 2cosecx

19.

\frac{sinA}{1+cosA} + \frac{1+cosA}{sinA}=\frac{2}{sinA} \\=> \frac{sinA}{1+cosA} + \frac{1+cosA}{sinA} - \frac{2}{sinA} \\ = 0\\=> \frac{sinA}{1+cosA} + (\frac{1+cosA}{sinA} - \frac{2}{sinA} \\) = 0\\=> \frac{sinA}{1+cosA} + \frac{1+cosA-2}{sinA} = 0\\=> \frac{sinA}{1+cosA} +\frac{cosA-1}{sinA} = 0\\=> \frac{sin^{2} A+(cosA-1)(1+cosA)}{(1+cosA)sinA}=0\\=> \frac{sin^{2} A+cos^{2} A-1}{(1+cosA)sinA}=0\\=> \frac{0}{(1+cosA)sinA} =0\\

=> The clause is correct

20. Do the same (18)

21. Left = \frac{1}{cosecA+cotA} = \frac{1}{\frac{1}{sinA}+\frac{cosA}{sinA}  } = \frac{1}{\frac{1+cosA}{sinA} }= \frac{sinA}{1+cosA}

Right = cosecA-cotA = \frac{1}{sinA}-\frac{cosA}{sinA}= \frac{1-cosA}{sinA}   \\

Same with (16) => Left = Right => The clause is correct

22. Do the same (21)

Too long, i'm so lazy :))))

5 0
3 years ago
Please help me with this ty
Andrej [43]
7x12 = 84
So the answer is D.
6 0
2 years ago
Read 2 more answers
brian and brenda are having a lemonade sale. brenda sells 20 cups of water in 2 hours. how many cups of lemonade did she sell pe
ruslelena [56]

Answer:

She sold 10 cups per hour

Step-by-step explanation:

To find the number per hour, divide the total sold by the total number of hours.

20 cups/2 hours = 10 per hour

6 0
2 years ago
Marcus spent 10 hours doing his homework last week. This week he spent 11 hours doing homework. He says that he spent 110% more
8_murik_8 [283]
No he did not spend 110% more time doing homework if he did it would be 12hrs to find this put 11 in its decimal form and multiply it by 110 =12.1 
3 0
3 years ago
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