Define unit vectors along the x-axis and the y-axis as
![\hat{i} , \, \hat{j}](https://tex.z-dn.net/?f=%5Chat%7Bi%7D%20%2C%20%5C%2C%20%5Chat%7Bj%7D)
respectively.
Then the vector from P to Q is
![\vec{PQ} = (-13+5)\hat{i} + (10-5)\hat{j} = -8\hat{i} + 5\hat{j}](https://tex.z-dn.net/?f=%5Cvec%7BPQ%7D%20%3D%20%28-13%2B5%29%5Chat%7Bi%7D%20%2B%20%2810-5%29%5Chat%7Bj%7D%20%3D%20-8%5Chat%7Bi%7D%20%2B%205%5Chat%7Bj%7D)
In component form, the vector PQ is (-8,5).
The magnitude of vector PQ is
√[(-8)² + 5²] = √(89) = 9.434
Answer:
The vector PQ is (-8, 5) and its magnitude is √89 (or 9.434).
Answer:
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Answer:
Step-by-step explanation: so simplyfy it to s/-1=2 so that means that s=2*1 so the answer is 2
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Answer:
5/12 chanch
Step-by-step explanation:
5+4+3 = 12
5 blue balls
5 out of 12
Answer:
x = 23
Step-by-step explanation:
CU + UB = CB
Since U is the midpoint that means CU = UB = 18
18+ 18 = 2x-10
36 = 2x-10
Add 10 to each side
36+10 = 2x
46 =2x
Divide by 2
23 = x