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Llana [10]
4 years ago
11

Given the inequality below: 3x-y>4 Which is the graph of the solution set?

Mathematics
1 answer:
OLga [1]4 years ago
6 0

Answer:

A shaded region below a dashed line (y <3x-4)

Step-by-step explanation:

For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.

Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.

In this case what we have here is an open region, as the graph below shows.

3x-y>4 =-y>4-3x∴y<3x-4

Setting a value for x

3x-4=0

3x=4

3x/3=4/3

x=4/3 (slope)

(4/3,0)

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Suppose that x and y vary inversely and that y=1/6 when x=3. Write a function that models the inverse variation and find y when
juin [17]

Answer:

The Inverse variation states a relationship between the two variable in which the product is constant.

i.e x \propto \frac{1}{y}

then the equation is of the form: xy = k where k is the constant of variation.

As per the given information: It is given that x and y  vary inversely and that y = 1/6 when x = 3.

then, by definition of inverse variation;

xy = k                                      ......[1]

Substitute the given values we have;

3 \cdot \frac{1}{6} = k

\frac{1}{2} = k

Now, find the value of y when x = 10.

Substitute the given values of x=10 and k = 1/2, in [1] we have;

10y = \frac{1}{2}

Divide both sides by 10 we get;

y = \frac{1}{20}

therefore, a function that models the inverse variation is; xy = \frac{1}{2} and value of  y = \frac{1}{20} when x = 10.



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