Question

Helaine graphed the equation 12x – 4y = 3. What was the slope of Helaine’s line?\

Answer 1

Answer:  The required slope of the given line is 3.

Step-by-step explanation:  Given that Helaine graphed the following equation :

$12x-4y=3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the slope of the line.

We know that

the slope-intercept form of a straight line is given by

$y=mx+c,$ where m is the slope of the line.

From equation (i), we have

$12x-4y=3\\\\\Rightarrow 4y=12x-3\\\\\Rightarrow y=\dfrac{12x-3}{4}\\\\\\\Rightarrow y=3x-\dfrac{3}{4}.$

Comparing with the slope-intercept form, we get

slope, m = 3.

Thus, the required slope of the given line is 3.

Answer 2

Answer:

$\large\boxed{\text{The slope}\ m=3}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have the equation of a line in the standard form:

$12x-4y=3$

Convert to the slope-intercept form:

$12x-4y=3$         subtract 12x from both sides

$-4y=-12x+3$        divide both sides by (-4)

$y=\dfrac{-12}{-4}x+\dfrac{3}{-4}\\\\y=3x-\dfrac{3}{4}$