For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.
For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).
Thus, there are 16 possible sums when three six-sided dice are rolled.
Therefore, from the pigeonhole principle, <span>the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.
The pigeonhole principle states that </span><span>if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.
That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.
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Answer:
(i) Yes
(ii) Yes
Step-by-step explanation:
We are given that
AB=AC
(i)D is the mid-point of BC
BD=DC
In triangle ADB and triangle ADC
AD=AD
Reason: Reflexive property
BD=DC
Reason:Given
AB=AC
Reason: Given
ADB
ADC
Reason:SSS postulate
Yes, triangle ADB is congruent to triangle ADC
(ii) Angle B=Angle C
Reason: CPCT
Yes , angle B=angle C
Answer:
129.99
Step-by-step explanation:
129.99 rounds to 130 because the 9 in the hundredths place causes the 9 in the tenths place to round up, making the number 130.0.
It's actually 2268 square inches, or in with a little two in the corner
Answer: I got 76.
Step-by-step explanation: