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Rudiy27
3 years ago
5

1 and 1/3 mineus 3/4

Mathematics
2 answers:
Katen [24]3 years ago
6 0

Answer:

1\frac{1}{3}-\frac{3}{4}=\frac{7}{12}

change 1\frac{1}{3} into \frac{4}{3}

=\frac{4}{3}-\frac{3}{4}

get like denominators:

12

\frac{16}{12}-\frac{9}{12}

16 - 9 = 7

<em>Hope this helps and have a great day!!!</em>

Murljashka [212]3 years ago
4 0

Answer:

7/12

Step-by-step explanation:

1 1/3 - 3/4

= 4/3 - 3/4

= 16/12 - 9/12

= 7/12

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Can someone help me please
Klio2033 [76]

Step-by-step explanation: the awnser is 70 because 69 and 71 is in the outside of 70 therefore it's 70 there u go

8 0
2 years ago
4. (-5, 2) and (-5, 6)
IgorLugansk [536]

Answer:

( 4, 5 ) -( 5, 6 ) =7,15

Step-by-step explanation:

5 0
2 years ago
John and Annie have two distinguishable ponds. Initially, each of the ponds contains four ducks and five geese. John first picks
Sladkaya [172]

Answer: 4/9

Step-by-step explanation:

The probability that annie picks a duck Pt= the probability of picking a duck without accounting for the added one (Po)+ probability of picking the added bird and it's a duck(Pi)

Pt = Po+Pi

Since the total number of birds in the right pond is 10 after the addition of one by john

Po= 4/10

Pi= the of john adding a duck × the probability of annie picking the added bird

Pi= 4/9 × 1/10

Pi = 4/90

Pt= 4/10 + 4/90

Pt = (36+4)/90

Pt=40/90

Pt= 4/9

(This implies that the probability of picking a duck remain the same even after the addition of one bird from the left ponds because they both have equal proportions of duck and geese i.e the initial number of duck and geese in both right and left ponds are 4 and 5 respectively)

Thanks.

4 0
3 years ago
The yearbook club had a meeting. The meeting had 24 people, which is three-fourths if the club. How many people are in the club?
Contact [7]

Answer:

18

Step-by-step explanation:

24*3/4=18

3 0
3 years ago
As part of the underwriting process for insurance, each prospective policyholder is tested for high blood pressure. Let X repres
xxTIMURxx [149]

Answer:

0.053

Step-by-step explanation:

This is a geometric distribution problem.

I'm geometric distribution problem,

E(X) = 1/p

Where;

E(X) is expected value and p is probability of success

Thus;

1/p = 12.5

p = 1/12.5

p = 0.08

Now, to find the probability that the sixth person tested is the first one with high blood pressure, we will use the probability formula in geometric distribution which is;

P(X = k) = qⁿ•p

q = 1 - p

q = 1 - 0.08

q = 0.92

Thus;probability that the sixth person tested is the first one with high blood pressure will be expressed as;

P(X > 5) = (0.92^(5)) × 0.08

P(X > 5) = 0.053

3 0
3 years ago
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