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hoa [83]
3 years ago
9

-5 < x - 4 greater than it equal 1

Mathematics
1 answer:
saul85 [17]3 years ago
6 0

We have expression -5 < x - 4 \geq 1 that renders the system of inequalities,

\begin{cases}-5 < x - 4 \\x - 4 \geq 1\end{cases}

Which can be simplified to,

\begin{cases}x > -1 \\x \geq 5\end{cases}

So what we get is something greater than -1 and at the same time greater or equal to 5, so the solution is,

x\in(\infty,-1)\cap(\infty, 5]=\boxed{(\infty,5]}.

Hope this helps.

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Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
4 years ago
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Pregunta 4 (1 punto)
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Answer:

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3 years ago
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By selling a watch in Rs 150 and Rs 200 loss and profit are happened
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Answer:

Rs 175

Step-by-step explanation:

Suppose the cost is x and at Rs150 the loss is 150-x (this should be a negative number).

At Rs200, the profit is 200-x.

So we have an equation: minus 150 minus x is equal to 200 minus x.

To solve the equation, the cost price X is Rs175.

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3 years ago
Write an equation to represent the following : 30 students can fit on a bus . If b buses are used and 3 students were left over
anzhelika [568]
30b+3= s

It would be thirty students times the number of buses, with an addition of 3 students equal to the total number of students when on the field trip.

I hope this helps!
~cupcake
6 0
3 years ago
A store sells laptops for $720 each. This price is 20 percent more than what it cost the store to buy each of them. Before the n
Pani-rosa [81]

It would cost an employee $443.52 to purchase one of these laptops at the sale.

The selling price of the laptops is $720 each. The cost price is 20 percent more than the cost price.

Cost price = Selling price - 20% of cost price

Cost price = 720 - 20% * 720 = $576

At the release, the laptops are at 23% off the store's cost. Hence:

Price of laptop at release = 576 - 23% of 576

Price of laptop at release = $443.52

It would cost an employee $443.52 to purchase one of these laptops at the sale.

Find out more at: brainly.com/question/20286603

7 0
3 years ago
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