You have this....
√x > 8
This means that the square root of something is greater than 8.
So plug in everything for x and find the answer.
Anything 64 and below is NOT THE ANSWER.
√64 = 8, and 8 is not greater than 8, so anything 64 and below is wrong.
So the answer is...
D and F.
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
73℅ of 58
= (73/100) × 58
= (73×58)/100
= 4234/100
= 42.34
Answer:
I think the answer is D.) 7/8 mile
Step-by-step explanation:
If you make the mixed numbers improper fractions, 2 and 1/8 is 17/8, 1 and 1/4 (2/8) is 10/8, then you subtract the numerators and keep the denomitators the same to get 7/8 mile (sorry if I spelt something wrong)
10 whole sandwiches can be made with 2 pounds of cheese if each sandwhich has 3 ounces of cheese on it.
2 pounds = 32 ounces
32/3 = 10.67
