-18-6k= 1+3k
9k=-19
k=-19/9
k=-2 and 1/9
(y^5-1)(y^5+8)............
The distance (d) traveled by the airplane is the product of multiplying the speed (s) and the trip took (h). The equation is shown below,
d = s x h
Substitute the known values to the equation,
637.5 miles = (150 mile/ hour) x h
Manipulating the equation,
h = (637.5 miles) / (150 mile/ hr)
h is equal to 4.25 hours.
