The value of P(4, 6) when the two number cubes are tossed is 1/36
<h3>How to determine the probability?</h3>
On each number cube, we have:
Sample space = {1, 2, 3, 4, 5, 6}
The individual probabilities are then represented as:
P(4) =1/6
P(6) =1/6
The value of P(4, 6) when the two number cubes are tossed is:
P(4, 6) = P(4) * P(6)
This gives
P(4, 6) = 1/6 * 1/6
Evaluate
P(4, 6) = 1/36
Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36
Read more about probability at:
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Answer:
B. 88.5
Step-by-step explanation:
first we add all the numbers :
(79 +80 +92 +92 +81 +100 +88 +98 +71 + 100+91+90) over 12
= 1062 over 12
= 88.5
[why over 12? because there's 12 numbers]
Answer:
x = 4 and 3
Step-by-step explanation:
[7±√(-7)²-4(1)(12)]/2
x = 4, 3
