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Harrizon [31]
3 years ago
15

What numbers that are in both the 2s and the 5s pattern​

Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer:

10 20 30 40 50 60 70 80 90 100 and the list goes on

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CAN SOMEONE GOOD AT MATH HELP PLEEESE!!
Rufina [12.5K]

Answer: 1 .Thus for a graph to have an Euler circuit, all vertices must have even degree. The converse is also true: if all the vertices of a graph have even degree, then the graph has an Euler circuit, and if there are exactly two vertices with odd degree, the graph has an Euler path.

2. A graph has an Euler circuit if and only if the degree of every vertex is even. A graph has an Euler path if and only if there are at most two vertices with odd degree.

Step-by-step explanation:

Can i have branily plz

7 0
2 years ago
What is the slope of the line graph in this picture?
MrMuchimi

Answer:

-5/4

Step-by-step explanation:

y2 - y1

x2 - x1

________

-2 - 3 = -5

5 - 1 = 4

Slope = -5/4

7 0
3 years ago
What is 7 over 10 as a decimal
Inessa05 [86]
.70 yup that's it that's the answer
4 0
3 years ago
A line passes through the point (–6, –3) and has a slope of 2/3 . Which point is on the same line?
navik [9.2K]

Answer:

The point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

Step-by-step explanation:

We know that the slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given

  • The point (-6, -3)
  • The slope m = 2/3

Using the point-slope form

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

  • m = 2/3
  • (x₁, y₁) = (-6, -3)

substituting the values m = 2/3 and the point (-6, -3)  in the point-slope form

y-y_1=m\left(x-x_1\right)

y-\left(-3\right)=\frac{2}{3}\left(x-\left(-6\right)\right)

y+3=\frac{2}{3}\left(x+6\right)

Subtract 3 from both sides

y+3-3=\frac{2}{3}\left(x+6\right)-3

y=\frac{2}{3}x+4-3

y=\frac{2}{3}x+1

comparing with the slope-intercept form y=mx+b

Here the slope = m = 2/3

Y-intercept b = 1

We know that the value of y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

Given the line

y=\frac{2}{3}x+1

at x = 0, y = 1

Thus, the point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

5 0
2 years ago
Show work and factor ?
kvasek [131]
5\cdot\dfrac{x^2-2x}{6}:\dfrac{3x-6}{x}=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3x-6}\\\\=5\cdot\dfrac{x(x-2)}{6}\cdot\dfrac{x}{3(x-2)}=\dfrac{5\cdot x\cdot x}{6\cdot3}=\dfrac{5x^2}{18}
4 0
3 years ago
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