All categories

2 years ago

-please help im so dum dum and id like therapy < <<<<<<<<33333333 TYY

Mathematics

1 answer:

Molodets [167]2 years ago

7 0

Answer:

Step-by-step explanation:

-40

−20−8-12

−28−12

-40

You might be interested in

How many pages should the manufacturer advertise for each cartridge if it wants to be correct 99% of the time

PolarNik [594]

The manufacturer should advertise 13811 pages for each cartridge if it wants to be correct 99% of the time

z-score is the number of standard deviations from the mean value of the reference population

99%=0.99

The z-value associate with 0.99 is 2.33:

2.33 = (X - 12425) / 595:

X - 12425 = 2.33 * 595

X = (2.33 * 595) + 12425

X = 138111

Therefore, The manufacturer should advertise 13811 pages for each cartridge if it wants to be correct 99% of the time

Learn more about the Manufacturer here

brainly.com/question/19584679

#SPJ4

7 0

1 year ago

PLZZZ ANSWER FAST U WILL GET BRAINLIEST A basket contains seven apples and eight peaches. You randomly select one piece of fruit

sergey [27]

1/12? Tell me if that’s right I’m not that good at it but I’m pretty sure it’s 1/12

6 0

2 years ago

Read 2 more answers

Solve the following please:

dalvyx [7]

Answer:

most likely b

Step-by-step explanation:

the more than symbol tells me that it is going to move past 10.

8 0

1 year ago

Jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest w

faltersainse [42]

40 x 5280 = 211200 feet per hour

211200 / 3600 = 58.666 = 59 feet per second

5 0

2 years ago

A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de

marin [14]

Answer:

$\frac{23}{4}$ feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 $\frac{1}{2}$ feet

= $\frac{5}{2}$ feet

The depth of the fish to its initial position at 4:00 pm = 3 $\frac{1}{4}$ feet

= $\frac{13}{4}$ feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

= $\frac{5}{2}$ + $\frac{13}{4}$

= $\frac{10 + 13}{4}$

= $\frac{23}{4}$

The position of the fish with respect to the water's surface at 4:00 pm is $\frac{23}{4}$ feet.

8 0

2 years ago