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kolezko [41]
3 years ago
5

A sample of 3 different bulbs is randomly selected from a group containing 8 that are defective and 22 that have no defects. Wha

t is the probability that at least one of the bulbs is defective?Round answer to three decimal places.
Mathematics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

Probability of drawing non defective bulb

=90/100×89/99×88/98×...........×82/92..........(i)=90/100×89/99×88/98×...........×82/92..........(i)

Now the probability of drawing at least one bulb will be defective

=1−(i)=1−90/100×89/99×88/98×...........×82/92

1−(90/100⋅89/99⋅…⋅83/93)

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Answer:

Her mom's candle has more citrus in it. Peppermint isn't a citrus scent.

Step-by-step explanation:

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3 years ago
Blake bought a coat on sale for 30% off the retail price. If he paid $130, what was the original retail price?
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$169, you do 10% and times it 3 times to get 30 then add 9
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Write the original equation of -18x-15= -87
Sunny_sXe [5.5K]

Answer:

x=4

Step-by-step explanation:

-18 x 4 x -15 = -87

8 0
3 years ago
Read 2 more answers
EMERGENCY momoninos operations 1.) 2a-3b divided by 6 2.) 4m+5n divided by 12 3.) 5m-4x divided by -3 4.) 4x+8y-3z divided by 9
faltersainse [42]

Answer:

1) (a/3) - (b/2)

2) (m/3) + (5n/12)

3) (-5m/3) + (4x/3)

4) (4x/9) + (8y/9) - (z/3)

5) (-5a/8) + (-3b/8) + (-3c/2)

Step-by-step explanation:

1) 2a-3b divided by 6

(2a-3b)/6 = (2a/6) - (3b)/6 = (a/3) - (b/2)

2) 4m+5n divided by 12

(4m+5n)/12 = (4m/12) + (5n/12) = (m/3) + (5n/12)

3) 5m-4x divided by -3

(5m-4x)/(-3) = (-5m/3) + (4x/3)

4) 4x+8y-3z divided by 9

(4x+8y-3z)/9 = (4x/9) + (8y/9) - (3z/9) = (4x/9) + (8y/9) - (z/3)

5) 5a+3b+12c divided by -8

(5a+3b+12c)/(-8) = (-5a/8) + (-3b/8) + (-12c/8) = (-5a/8) + (-3b/8) + (-3c/2)

8 0
3 years ago
Researchers once surveyed students on which superpower they would most like to have. The following two-way table displays data f
GenaCL600 [577]

Answer:

The percent of students in the sample who were male is 48%.

Step-by-step explanation:

The complete question is:

Researchers once surveyed 100 students on which superpower they would most like to have. The following two-way table displays data for the sample of students who responded to the survey.

Superpower    Male    Female    TOTAL

Fly                      26           12           38

Invisibility           12           32           44

Other                  10            8            18

TOTAL               48           52          100

What percent of students in the sample were male?

Solution:

The probability of an event <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The number of males in the sample is, <em>n</em> (M) = 48.

Total number of students, <em>N</em> = 100.

Compute the probability of selecting a male student as follows:

P(M)=\frac{n(M)}{N}\\

          =\frac{48}{100}\\\\=0.48

Then the percent of students in the sample who were male is:

\text{Percent of Males}=P(M)\times 100\%

                          =0.48\times 100\%\\\\=48\%

Thus, the percent of students in the sample who were male is 48%.

4 0
3 years ago
Read 2 more answers
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