All categories

3 years ago

A news site offers a subscription that costs $28.50 for 6 months. What is the unit price per month.

Mathematics

1 answer:

crimeas [40]3 years ago

7 0

Divide the total cost by the amount of months
28.5 divided by 6=4.75

You might be interested in

Pls answer my other question before this one. i need dem smart people and if you want to answer the qeustion on this one the her

lozanna [386]

Answer:

do you still need this answer to this question and where is the other question??

Step-by-step explanation:

4 0

2 years ago

Which equation should be used to solve this problem?

maks197457 [2]

Answer: 56=4d

Explanation:

Dorothy is 14

7 0

3 years ago

Read 2 more answers

Ms. Tyson has a part time job selling cars. She earns a commission of 0.6% on all her sales. If her sales for last week was $281

In-s [12.5K]

Based on the information given her commission check is $1,689.8.

Using this formula

Commission check=Commission earned× Sales

Where:

Commission earned=0.6% or 0.006

Sales=$281,634

Let plug in the formula

Commission check= 0.006×$281,634

Commission check=$1,689.8

Inconclusion her commission check is $1,689.8.

Learn more here:brainly.com/question/24030244

8 0

2 years ago

Whats the volume ?????

tiny-mole [99]

Answer:

Step-by-step explanation:

Multiply the three dimensions

12 x 6 x 8 = 576 cm^3

4 0

2 years ago

Read 2 more answers

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago