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AveGali [126]
3 years ago
10

Pls sovle thankyou number 7

Mathematics
2 answers:
VladimirAG [237]3 years ago
6 0

-6x expnonent 3 becomes -216

so, the equation is know

-216 r exponent 7 / 3x

r-x is x

so know its -216-3x you get - 219x

Aleks [24]3 years ago
4 0

Answer:

\frac{-6x^3r^7}{3x}=-2r^7x^2

Step-by-step explanation:

hope this helps

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The measures of two angles in a triangle are 32o and 78o. Which of the following equations could be used to find the measure of
Korvikt [17]

Answer:

32+78+x=180

Step-by-step explanation:

All triangle angles add up to 180, so add 78 and 32 then subtract it from 180 to get x, which in another form is 32+78+x=180.

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3 years ago
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Which of these pairs of points defines a line with slope 0? OA) (1, 4) and (-4,4) OB) (4, 1) and (-4, 4) OC) (-1,4) and (4, -4)
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4

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which transformation of the function f(x) is the rigid motion: 2f(x)+3, f(x/2)+1, 2f(x/2), or f(x-1/2)+3
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Answer is choice D. The other choices involve dilations, or scalings, which basically make the graph taller or flatter depending on what the scale factor is. In the case of f(x-1/2)+3, we shift f(x) to the right 1/2 a unit and up 3. 
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Write the slope intercept form of the equation with slope 8 and y intercept (0,7)
Elanso [62]

Answer:

y=8x+7

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Use the form y=mx+b

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4 0
3 years ago
BD−→− bisects ∠ABC such that m∠ABD = (4x−5)∘ and m∠DBC = (3x+2)∘.
Rzqust [24]

Answer:

\angle ABC=(46)^{\circ}

Step-by-step explanation:

Given: BD bisects \angle ABC

\angle ABD=(4x-5)^{\circ}\\\angle DBC=(3x+2)^{\circ}

To find: \angle ABC

Solution:

A bisector of an angle divides it into angles of equal measures.

As BD bisects \angle ABC, \angle ABD=\angle DBC

Put \angle ABD=(4x-5)^{\circ}\,,\,\angle DBC=(3x+2)^{\circ}

\angle ABD=\angle DBC\\(4x-5)^{\circ}=(3x+2)^{\circ}\\4x-3x=2+5\\x=7^{\circ}

So,

\angle ABD=(4x-5)^{\circ}=(4(7)-5)^{\circ}=(28-5)^{\circ}=(23)^{\circ}\\\angle DBC=(3x+2)^{\circ}=(3(7)+2)^{\circ}=(21+2)^{\circ}=(23)^{\circ}

\angle ABC=\angle ABD+\angle DBC\\=(23)^{\circ}+(23)^{\circ}\\=(46)^{\circ}

3 0
3 years ago
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