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igor_vitrenko [27]
3 years ago
9

Is this statement True. A system of independent equations has infinite solutions

Mathematics
1 answer:
Misha Larkins [42]3 years ago
7 0

Answer:

It's true.

Step-by-step explanation:

You might be interested in
15 cm<br> 4 cm<br> cm<br> V=____cm3
bonufazy [111]

Answer:

V=(πr^2 x h)/3

lets use π as 3.14 cause I dont know what pi u using

3.14 x 4^2 x 15 = 753.6/3 = 251.2

If you're using π as your pi, than just replace 3.14 by π on calculator

Hope that answers your question

8 0
3 years ago
In ∆ABC, point D is the centroid. If (AE) ̅=15, (BF) ̅=27, and (CD) ̅=8, find the following lengths
Anna71 [15]

Answer:

5,18,12 cms are the answer.

Step-by-step explanation:

Given is a triangle ABC.  Point D is the centroid.  

E,F and G are midpoints of CB, BA and AC respectively.

AE, BF and CG are medians of the triangle.

We know that centroid divides the median in the ratio 2:1

Using this we find that AD:DE = 2:1

Or AD+DE:DE = (2+1):1

AE:DE =3:1

15:DE = 3:1 . Hence DE =5 cm.

On the similar grounds we find that DF = 1/3 BF = 9

Hence BD = DF-BF = 27-9 =18 cm

and also

CG = 3/2 times CD = 12 cm.

7 0
3 years ago
A sales associate is given a $500 hiring bonus with a new job. She earns an average commision of $250 per week for the next 12 w
allsm [11]
$3500 250 x 12 + 500
4 0
3 years ago
What Are Some Great Algebra 1 Math source i can use for 9th grade math​
stepan [7]

Answer:

Khan Academy is a great website for Algebra l math

If you have the time and money Kumon is a good in-person learning assistance (I-H level is about algebra I)

Step-by-step explanation:

4 0
2 years ago
Find the diameter(s) of circle O.
schepotkina [342]

Answer:

The diameter of the circle O is <em>12 units</em>

Step-by-step explanation:

There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of  

BC=6\sqrt{2}

and the triangle B0C is right

<u>Relations in the Circle</u>

The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.  

Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r

Applying Pythagoras's theorem:

BC^2=r^2+r^2=2r^2

Thus we have

2r^2=(6\sqrt{2})^2

2r^2=72

r^2=36

r=6

The diameter of the circle O is D=2(6) = 12 units

5 0
3 years ago
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