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3 years ago

12

I have 5 digits. My 4s are worth 4 (10000) and 4 ×10. My 3 is worth 3. The other is worth one tenth as much. My other digit is a

2

1 answer:

likoan [24]3 years ago

4 0

The number is 40243 :)
hope this helps

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A study on students drinking habits wants to determine the true average number of alcoholic drinks all uf underclassmen students

frutty [35]

Answer: 16

Step-by-step explanation:

Standard deviation is 2

Margin error for the problem is 1

Probability 95%, that means thet the siginficance level α is 1 – p

α = 1 – 0.95 = 0.05

margin of error (ME) can be defined as follows

ME = Z(α/2) * standard deviation/ √n

Where n is the sample size

Z(0.05/2) = Z(0.025)

Using a z table Z = 1.96

Now, replacing in the equation and find n

1 = 1.96 * 2/ √n

1 = 3.92 / √n

√n = 3.92

n = 3.92^2

n = 15.36 = 16

i hope this work for you

8 0

2 years ago

Which graph is given by the equation y = −4x + 4?

Elodia [21]

Answer:

The correct answer is B buddy.

good luck♥️♥️♥️♥️♥️.

6 0

3 years ago

A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week

Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of individuals who work at home at least once per week = $\frac{41}{250}$ = 0.164

n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<em>99% confidence interval for p</em> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ , $0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ ]

= [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0

2 years ago

A medical website states that 40% of U.S. adults are registered organ donors. A researcher believes that the proportion is too h

alexgriva [62]

Answer:

Pvalue = 0.193

There is not enough evidence to conclude that the proportion of registered organ donors is less than 40%

Step-by-step explanation:

H0 : p = 0.4

H1 : p < 0.4

Test statistic :

z=pˆ−p/√p(1−p)/n

pˆ = 74 / 200 = 0.37

Z = (0.37 - 0.40) / √(0.40(1 - 0.40) / 200

Z = - 0.03 / √0.0012

Z = - 0.03 / 0.0346410

Z = - 0.866

Test statistic = -0.866

The Pvalue :

P(Z < -0.866) = 0.193

α - level = 0.05

If Pvalue < α ; Reject H0

Since Pvalue > α ; There is not enough evidence to conclude that the proportion of registered organ donors is less than 40%

3 0

2 years ago

6 identical toys weigh 1.8 kg how much would 1 toy weigh using grams

kaheart [24]

Solution:

Given that, 6 identical toys weigh 1.8 kg

we know that, 1kilogram = 1000 grams

6 identical toys weigh in grams

$1.8 * 1000 =1800$

6 identical toys weigh 1800 grams

then calculating the weight of 1 toy by unitary method ,

weight of 1 toy = $\frac{1800}{6} = 300$ grams.

Hence, 1 toy would weigh 300 grams.

6 0

3 years ago

Read 2 more answers