Question

At a busy street corner, one of every hundred jaywalkers will be hit when they cross. What is the probability of a jaywalker not being hit if he makes a round trip daily for thirty days? (0.01)30 (0.99)30 (0.9801)30

Answer 1

Answer: Last option

$p = (0.9801) ^ {30}$

Step-by-step explanation:

the probability of a jaywalker being hit is

$P = \frac{1}{100} = 0.01$.

So the probability of a jaywalker not being hit is:

$P '= 1-0.01$

$P '= 0.99$

As in this experiment the probability of each trial is independent then, the probability that it is not a jaywalker will not be hit if it makes a round trip is:

$P '= (0.99) (0.99) = 0.9801$

$P '= 0.9801$

If this experiment is repeated for 30 days then the probability that it is not a jaywalker will not be hit if it makes a round trip is:

$p = (0.9801) ^ {30}$