The quadcopter's average velocity is given in terms of change in position by
where 
, the difference in the quadcopter's final and initial positions and 
.
The 
-component of the average velocity is 2.70 m/s, so
and the 
-component is -2.50 m/s, so
The period is equal to 2pi/n, where n is the coefficient of t. In this case pi/2. Therefore the period in this example is 4. Frequency is equal to 1/period. Hence the frequency for this problem is 1/4
Answer:
4 pounds of lime and 5 pounds of pears
Step-by-step explanation:
I + P = 9
0.5l + 1.5P = 9.5
I = 9 - P
0.5(9 - P) + 1.5P = 9.5
4.5-0.5P + 1.5P = 9.5
4.5 + P (1P) = 9.5
P = 9.5-4.5 = 5
I = 9 - 5 = 4
Answer: 4 pounds of lime and 5 pounds of pears
X = unknown number
10x - 16 = 2x
Subtract 10x from both sides to isolate the variable on the right side of the equation.
-16 = -8x
Divide both sides by -8 to get x alone.
2 = x
What's the shape of what the farmer is fencing?
