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3 years ago

Item 15 Fill in the blank so that the ordered pair is a solution of y=12x+2. ( , 14)

Mathematics

1 answer:

maxonik [38]3 years ago

7 0

Answer:

(1, 14)

Step-by-step explanation:

If you substitute the 14 in;

14 = 12x+2

-2 -2

12 = 12x

/12 /12

1 = x

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the arlington drama club is selling tickets to an upcoming play. They can sell at most 250 tickets. The adult tickets for $15 ea

allochka39001 [22]

Number of adult tickets = 75

Number of student tickets = 175

Solution:

Let x represents the number of adult tickets and

y represents the number of student tickets.

Total number of tickets sold = 250

⇒ x + y = 250 – – – – (1)

Cost of adult ticket = $15

Cost of student ticket = $5

Total cost of collection = $2000

15x + 5y = 2000 – – – – (2)

Multiply equation (1) by 5

⇒ (1) × 5 5x + 5y = 1250 – – – – (3)

Subtract equation (3) from equation (2), we get

15x + 5y – 5x – 5y = 2000 – 1250

⇒ 10x = 750

⇒ x = 75

Substitute x = 75 in equation (1), we get

⇒ 75 + y = 250

⇒ y = 250 – 75

⇒ y = 175

Number of adult tickets = 75

Number of student tickets = 175

6 0

3 years ago

Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0

drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

Step-by-step explanation:

The given is,

$2x+2y+z=- 2$ .......................................(1)

$-x-2y+2z=-5$ ......................................(2)

$2x+4y+z=0$ .........................................(3)

Step:1

Equation (2) is multiplied by -1 ( Eqn(2) × -1 )

$x+2y-2z=5$ .............................(4)

Subtract the equation (1) and (4)

$2x+2y+z=- 2$

$x+2y-2z=5$

( - )

$(2x-x)+(2y-2y)+(z+2z)=(-2-5)$

$x+3z=-7$ ......................(5)

Step:2

Equation (2) is multiplied by -2 ( Eqn(2) × -2)

$2x+4y-4z=10$ ........................(6)

Subtract equation (6) and (3),

$2x+4y-4z=10$

$2x+4y+z=0$

( - )

$(2x-2x)+(4y-4y)+(-4z-z)= (10-0)$

$-5z=10$

$z = - \frac{10}{5}$

z = -2

From the equation (5),

$x+3z=-7$

$x+(3)(-2)=-7$

$x = -7+6$

x = -1

From equation (1),

$2x+2y+z=- 2$

Substitute x and z values,

$(2)(-1)+2y+(-2)=-2$

$2y - 4=2$

$2y=4-2$

$2y=2$

$y=\frac{2}{2}$

y = 1

Step:3

Check for solution,

$-x-2y+2z=-5$

Substitute x,y and z values,

$-(-1)-(2)(1)+(2)(-2)=-5$

$1-2-4=-5$

-5 = -5

Result:

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

8 0

4 years ago

If there are 12 inches in a foot,how many cubic inches are there in a cubic foot

Dvinal [7]

1728 inches hope this helps!

6 0

3 years ago

What conclusion can be derived by comparing the central tendencies of the two data sets?

valentinak56 [21]

B i hope this helps you

4 0

4 years ago

Read 2 more answers

On the number line, a bug A is moving in the positive direction from the point 0, and a bug Bis moving in the negative direction

m_a_m_a [10]

Answer:

20 seconds

Step-by-step explanation:

The speed of A is:

sA = 18 units / 3 seconds = 6 units/second

The speed of B is:

sB = -15 units / 3 seconds = -5 units/second

The relative speed is:

s = sA − sB

s = 6 units/second − (-5 units/second)

s = 11 units/second

The time for the distance between them to be 220 units is:

220 units = 11 units/second × t

t = 20 seconds

8 0

3 years ago