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3 years ago

What is the greatest common factor of 9 and 12

Mathematics

2 answers:

horrorfan [7]3 years ago

6 0

Answer: 3

Step-by-step explanation: To find the greatest common factor, or GCF of 9 and 12, simply list the prime factors for 9 and 12.

9 = 3 x 3

12 = 2 x 2 x 3

So, the GCF is 3, because 3 occurs the most as a factor.

Vladimir79 [104]3 years ago

5 0

The greatest common factor is 3

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What is the slope of the line that passes through the points (2, 2), and (4,2)

vfiekz [6]

Answer:

There is no slope. $m=0$

Step-by-step explanation:

$m=\frac{rise}{run}=\frac{2-2}{4-2}=\frac{0}{2}=0$

(2, 2) and (4,2) makes a horizontal line. All horizontal lines on a graph have no slope.

6 0

4 years ago

A manager randomly selected 25 large cash transactions at a bank that were made in January. The manager then carefully tracked d

Dmitriy789 [7]

Answer:

0.4629 = 46.29% probability that the manager finds more than two such transactions

Step-by-step explanation:

For each transaction, there are only two possible outcomes. Either there is a procedural error, or there is not. The probability of a procedural error on a transaction is independent of any other transaction. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A manager randomly selected 25 large cash transactions at a bank that were made in January.

This means that $n = 25$

The chance for a procedural error is 10%

This means that $p = 0.1$

What is the probability that the manager finds more than two such transactions?

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718$

$P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994$

$P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659$

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0718 + 0.1994 + 0.2659 = 0.5371$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5371 = 0.4629$

0.4629 = 46.29% probability that the manager finds more than two such transactions

4 0

3 years ago

Assume cos T = .45 and cos W = .89, both T and W are positive, and both T and W determine a terminal point in Quadrant 4. which

emmainna [20.7K]

As both $T$ and $W$ determine terminal points in the fourth quadrant, we know that both angles fall between $270^\circ$ and $360^\circ$ . We also know that $0$ for $270$ , and that $\cos x$ is strictly increasing along this interval.

This means that the angle with the larger cosine value must be closer to having a measure of 360 degrees than the angle with the smaller cosine value, so $W>T$ .

4 0

4 years ago

Read 2 more answers

Y=3(x-2)(x+1)(x-4) find all the zeros of the function

Akimi4 [234]

Answer:

All of the zeros would be 2, -1 and 4

Step-by-step explanation:

When you set each of the factors equal to zero solve for x. The only one you can't is 3 because $3\neq 0\\$

4 0

3 years ago

Please help this is due tomorrow

tia_tia [17]

Danielle had a percent error of 13.6 (farthest)
Iris had a percent error of 6.8
HB has a percent error of -2.3 (closest)

So the order is HB, Iris, and then Danielle

7 0

3 years ago