Question

What is √6 over √5 in simplest radical form

Answer 1

To start off, this fraction needs to be rationalized; you can't have a radical in the denominator. So, you multiply both the numerator & denominator by the same number (so as to not mess up the proportion of numerator:denominator; it's like multiplying by 1) & get the radical out of the denominator. What number would that be? sqrt5.
So we have (sqrt6/sqrt5)•(sqrt5/sqrt5).
To simplify that, we get (sqrt6•sqrt5)/(sqrt5•sqrt5).
This can be rewritten as:
sqrt(6•5)/sqrt(5•5)
= sqrt30/sqrt25
Now, sqrt25 = 5, so that problem is solved as such:
sqrt30/5
I'm thinking sqrt30 can't be simplified any further. If it can, do so.

Hope this helps!