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scoray [572]
3 years ago
6

Define the word factor mathmatically

Mathematics
2 answers:
lukranit [14]3 years ago
5 0
Factor is a integer / number being multiplied by another number
Nataliya [291]3 years ago
4 0
The word factor in mathematics means any two numbers that can be multiplied to get a product.

3 X 4 = 12

3 and 4 are the factors.
12 is the product.
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18.<br> Place parentheses in the following equation to<br> make it true.<br> 4 + 5 x 3-8 = 19
Simora [160]

Answer:

4+(5×3) -8=19 that's what I got

6 0
3 years ago
Determine the slope and the y-intercept. <br>y = 5x + 6
Cloud [144]
When that equation is graphed, it produces a straiught line.  The slope
of the line is 5, and the line intersects the y-axis at y=6.
7 0
3 years ago
Read 2 more answers
5^x + 5^x+1= 150<br> Find x<br> Help me pls i need soon<br> Tksss
raketka [301]

Answer:

x=2

Step-by-step explanation:

So we have the equation:

5^x+5^{x+1}=150

First, separate the second term:

5^x+(5\cdot5^x)=150

Let u equal 5ˣ. So:

u+5u=150

Combine like terms:

6u=150

Divide both sides by 6:

u=25

Substitute back u:

5^x=25

Take the base 5 logarithm of both sides:

\log_5(5^x)=\log_5(25)

The left cancels:

x=\log_5(25)

Evaluate the right:

x=2

So, our answer is 2.

And we're done!

5 0
3 years ago
I don't understand what this is?
m_a_m_a [10]
It's talking about box and whisker plot 
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5 0
3 years ago
A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
11Alexandr11 [23.1K]

Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

3 0
3 years ago
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