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schepotkina [342]
3 years ago
12

What is the shape 1 circular base and 1curved surface

Mathematics
2 answers:
swat323 years ago
6 0
Circular based pyramid I believe
sergey [27]3 years ago
3 0
Circular based
Curved surface

It would be a cone. 

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It says to solve each proportion which I forgot how to do. Please help.
skelet666 [1.2K]
You have to divide denominator by numerator to find the constant of proportionality.
7 0
3 years ago
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Please help me with these two math questions! Thank you ! :)
notka56 [123]
I think it might be c hope that helps you 
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3 years ago
What Is the width of 12 1/2 and 103 1/8
jolli1 [7]
Answer=8.25 or 8 1/4

Area=103 1/8
Length=12 1/2

Okay, so we know the Area and Length of a rectangle, and are just trying to solve for the width. 


The formula for the area of a rectangle is:
Area=length*width

Now lets fill in the data that we know

103 1/8=12 1/2 * width
to get the width by itself, divide both sides by 12 1/2
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8 0
3 years ago
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What are the zero(s) of the function 5x2-25x/x
Vikentia [17]
The answer is A: 5

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6 0
3 years ago
Find the Z-scores that separate the middle 61% of the distribution from the area in the tails of the standard normal distributio
professor190 [17]

Answer:

Z-scores between -0.86 and 0.86 separate the middle 61% of the distribution from the area in the tails of the standard normal distribution

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Middle 61%

Between the 50 - (61/2) = 19.5th percentile and the 50 + (61/2) = 80.5th percentile.

19.5th percentile.

Z with a pvalue of 0.195. So Z = -0.86

80.5th percentile.

Z with a pvalue of 0.805. So Z = 0.86.

Z-scores between -0.86 and 0.86 separate the middle 61% of the distribution from the area in the tails of the standard normal distribution

8 0
2 years ago
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