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2 years ago

Please help me:) 30 points

Mathematics

2 answers:

Alexeev081 [22]2 years ago

6 0

Answer:

your answer is C(N(h)) = 1400h +530

Step-by-step explanation:

Brut [27]2 years ago

5 0

Answer:

C(N(h)) = 1400h +530

Step-by-step explanation:

x = N(h), so substitute in the expression for N(h) to get x

C(N(h)) = 35(40h) + 530

=> 1400h + 530

now pray for my lazy brain to check work it is correct

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2 years ago

Read 2 more answers

6. The first quartile (rounded to the nearest tenth if needed) of the following data set is: 15. 16. 17. 23. 11. 19. 20. 15, 18,

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Answer:

Step-by-step explanation:

first of all arrange this data from ascending to descending order.

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2 years ago

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nikitadnepr [17]

Answer:

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2 years ago

Which of the following inequalities are true? Select all of the correct

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3 years ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

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cosФ = 0

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So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

2 years ago