Add −12 + 7. options: 19 −5 −19 5

$26,876 is invested, part at 9% and the rest at 5%. If the interest earned from the amount invested at 9% exceeds the interest e

Andre45 [30]

9514 1404 393

Answer:

$14,747 at 9%
$12,129 at 5%

Step-by-step explanation:

Let x represent the amount invested at 9%. Then the difference in interest amounts is ...

(9%)x -(5%)(26876 -x) = 720.78 . . . . . assuming a 1-year investment

0.14x -1343.80 = 720.78 . . . . . . . . . simplify

0.14x = 2064.58 . . . . . . . . . . . . . . add 1343.80

x = 14,747 . . . . . . . . . . . . . . . . divide by 0.14

$14,747 is invested at 9%; $12,129 is invested at 5%.

8 0

3 years ago

2².23 = (Type your answer using exponential notation. Simplify your answer.)

sveta [45]

Answer:

2^2 * 2^3 = 32

2^5 = 32

Step-by-step explanation:

2*2*2*2*2 = 32

5 0

2 years ago

Which three pairs of side lengths are possible measurements for the triangle?

katrin2010 [14]

Answer:

AB = 6, BC = 6

AB = 4, AC = 4√2

BC = 2√2, AC = 4

Step-by-step explanation:

The sides of an isosceles right triangle are in the ratio 1:1:√2 where √2 is the hypotenuse.

So if, for example, BC = 2√2, then AC = 2√2 * √2 = 4.

4 0

2 years ago

Find the midpoint of the segment between the points (8,−10) and (−10,−8) A. (−1,−9) B. (0,−6) C. (0,0) D. (−1,2)

Degger [83]

Answer:

Hey there!

We can use the midpoint formula to find that the midpoint is (-1, -9).

Let me know if this helps :)

4 0

3 years ago

Solve for x in the equation x squared minus 4 x minus 9 = 29. x = 2 plus-or-minus StartRoot 42 EndRoot x = 2 plus-or-minus Start

Furkat [3]

Answer:

$x=2$\pm$\sqrt{42}$

Step-by-step explanation:

The given equation is:

$x^{2} -4x-9=29\\\Rightarrow x^{2} -4x-9-29=0\\\Rightarrow x^{2} -4x-38=0$

Formula:

A quadratic equation $ax^{2} +bx+c=0$ has the following roots:

$x=\dfrac{-b+\sqrt D}{2a}\ and\\x=\dfrac{-b-\sqrt D}{2a}$

Where $D= b^{2} -4ac$

Comparing the equation with $ax^{2} +bx+c=0$

a = 1

b = -4

c= -38

Calculating D,

$D= (-4)^{2} -4(1)(-38)\\\Rightarrow D = 16+152 = 168$

Now, finding the roots:

$x=\dfrac{-(-4)+\sqrt {168}}{2\times 1}\\\Rightarrow x=\dfrac{4+2\sqrt {42}}{2}\\\Rightarrow x=2+\sqrt {42}\\and\\x=\dfrac{-(-4)-\sqrt {168}}{2\times 1}\\\Rightarrow x=\dfrac{4-2\sqrt {42}}{2}\\\Rightarrow x=2-\sqrt {42}$

So, the solution is:

$x=2$\pm$\sqrt{42}$

5 0

2 years ago