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Lana71 [14]
3 years ago
5

The length of a rectangle is 3 inches more that its width. The perimeter of the rectangle is at least 30 inches. Which inequalit

y shows the possible range of widths of the rectangle?
A. w ≥ 16.5 inches
B. w ≥ 13.5 inches
C. w ≥ 9 inches
D. w ≥ 6 inches
Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0
<span>Perimeter of a rectangle: 2(l + w)
</span>
2(l + w) ≥ 30 in
<span>

Simplify- divide both sides by 2.

l + w ≥ 15 in


Substitute (w + 3) into l so only 1 variable is used.

(w + 3) + w ≥ 15 in


Simplify further- add variables and subtract 3 from both sides.

2w ≥ 12 in


Divide both sides by 2.

w ≥ 6 in


Answer: D</span>
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1 jar of paint = 1 pint of paint
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2 years ago
Help please? 20 points
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Answer:

125.6637061 or 125.7

Step-by-step explanation:

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  125.6637061

7 0
3 years ago
the probability of picking rotten apple in a box is 1/100 .if there are 6 boxes containing 1200 apples each how many rotten appl
bulgar [2K]
<h3>Answer:</h3>

\huge{\boxed{72}}

<h3>Explanation:</h3>

First, find the total number of apples.  6*1200=7200

Now, multiply this by the probability of picking a rotten apple, which is \frac{1}{100}.  This is also the same as dividing by 100, or moving the decimal point two places to the left.  7200*\frac{1}{100}=72

This means that based on the probability given, 72 rotten apples will be picked.

7 0
2 years ago
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Josh has some nickels. He says they are worth exactly 33 cents. Can you tell if Josh is correct or not?
Katyanochek1 [597]

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8 0
3 years ago
Solve: x^+4/x-1 = 5/x-1
AlexFokin [52]
The first step for solving this equation is to determine the defined range.
\frac{ x^{4}  }{x-1} = \frac{5}{x-1}, x ≠ 1
Remember that when the denominators of both fractions are the same,, you need to set the numerators equal. This will look like the following:
x^{4} = 5
Take the root of both sides of the equation and remember to use both positive and negative roots.
x +/- \sqrt[4]{5}
Separate the solutions.
x = \sqrt[4]{5}           , x ≠ 1
x = -\sqrt[4]{5} 
Check if the solution is in the defined range.
x = \sqrt[4]{5} 
x = -\sqrt[4]{5} 
This means that the final solution to your question are the following:
x = \sqrt[4]{5}          
x = -\sqrt[4]{5} 
Let me know if you have any further questions.
:)
7 0
3 years ago
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