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3 years ago

Which statements are true based on the diagram? Select three options.

Mathematics

1 answer:

Aneli [31]3 years ago

5 0

Answer:

On Edge its:

Option A: Points N and K are on plane A and plane S.

Option C: Point P is the intersection of line n and line g.

Option D; Point's M, P, and Q are noncollinear.

Are Correct.

Step-by-step explanation:

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Cristina financed a $799 laptop with a 7.2% interest rate on a 2-year loan. If she can afford to make a $75 payment, how quickly

KatRina [158]

Your question is missing some elements but to answer the question I have to make an assumption.

Assuming that she make a monthly payment of $75.

The value of an loan at the end of the two year is given by

$FV=PV(1+r)^n$

where PV = $799, r = 7.2% = 0.072 and n = 2 years.

Thus,

$FV=799(1+0.072)^2=799(1.072)^2=799(1.149184)=\$918.20$

If she makes a monthly payment of $75, the number of months it will take her to pay off for her laptop is given by

$\frac{\$918.20}{\$75} =12.24\, months$

Therefore, it will take her 13 months to pay off for the laptop.

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3 years ago

Which verbal expression represents the algebraic expression 3y?

AlexFokin [52]

The algebraic expression 3y would be represented verbally by 3 multiplied by y!

5 0

3 years ago

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What is 2 1/2 - 1 1/8

Lady bird [3.3K]

Answer:

<h2>Convert the <em>mixed numbers</em> to </h2><h2><em>improper fractions</em>, </h2><h2>then find the <em>LCD</em> and combine.</h2>

<u />

<u>Exact Form:</u>

11/8

<u>Decimal Form:</u>

1.375

<u>Mixed Number Form:</u>

1 3/8

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3 years ago

How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?

MAVERICK [17]

Non-negative integers are positive integers or zero.

1. When $x_1=0,$ then there are such possible cases for $x_2$ and $x_3:$

$x_2=0,\ x_3=10;$
$x_2=1,\ x_3=9;$
$x_2=2,\ x_3=8;$
$x_2=3,\ x_3=7;$
$x_2=4,\ x_3=6;$
$x_2=5,\ x_3=5;$
$x_2=6,\ x_3=4;$
$x_2=7,\ x_3=3;$
$x_2=8,\ x_3=2;$
$x_2=9,\ x_3=1;$
$x_2=10,\ x_3=0.$

In total 11 solutions for $x_1=0.$

2. For $x_1=1,$ there are such possible cases for $x_2$ and $x_3:$

$x_2=0,\ x_3=9;$
$x_2=1,\ x_3=8;$
$x_2=2,\ x_3=7;$
$x_2=3,\ x_3=6;$
$x_2=4,\ x_3=5;$
$x_2=5,\ x_3=4;$
$x_2=6,\ x_3=3;$
$x_2=7,\ x_3=2;$
$x_2=8,\ x_3=1;$
$x_2=9,\ x_3=0.$

In total 10 solutions for $x_1=1.$

3. This process gives you

for $x_1=2$ - 9 solutions;
for $x_1=3$ - 8 solutions;
for $x_1=4$ - 7 solutions;
for $x_1=5$ - 6 solutions;
for $x_1=6$ - 5 solutions;
for $x_1=7$ - 4 solutions;
for $x_1=8$ - 3 solutions;
for $x_1=9$ - 2 solutions;
for $x_1=10$ - 1 solution.

4. Add all numbers of solutions:

$11+10+9+8+7+6+5+4+3+2+1=66.$

Answer: there are 66 possible solutions (with non-negative integer variables)

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3 years ago

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3 years ago

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