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Kay [80]
3 years ago
10

How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?

Mathematics
1 answer:
serious [3.7K]3 years ago
6 0
 To solve this problem you must use Permutation:
 
 You want to made 4 digit numbers with the digits 1, 2, 3, 4, 5, 6 and<span> no digit can be used more than once. So, we have:
 
 (A,B,C,D)

 A can variate in six (6) differents forms.
 B can variate in (6-1)=5 differents forms.
 C can variate 4 digits.
 D can variate 3 digits.
 
 Keeping this on mind, we have:
 
 =6!/2!
 =6*5*4*3
 =360
 
</span> The answer is: 360

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Leonardo wrote an equation that has an infinite number of solutions. One of the terms in Leonardo’s equation is missing, as show
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Let us suppose missing term is y

so it becomes - ( x-1) + 5 = 2 ( x+3) - y

let us now try solving it for x ( in terms of y )

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3 years ago
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