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3 years ago

10

How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?

1 answer:

serious [3.7K]3 years ago

6 0

To solve this problem you must use Permutation:

You want to made 4 digit numbers with the digits 1, 2, 3, 4, 5, 6 and<span> no digit can be used more than once. So, we have:

(A,B,C,D)

A can variate in six (6) differents forms.
B can variate in (6-1)=5 differents forms.
C can variate 4 digits.
D can variate 3 digits.

Keeping this on mind, we have:

=6!/2!
=6*5*4*3
=360

</span> The answer is: 360

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bixtya [17]

Using an exponential function, it is found that f(5.5) = 19.8.

<h3>What is an exponential function?</h3>

An exponential function is a function in which the growth rate is a percentage, modeled by:

$y = ab^x$

In which:

a is the initial value.

b is the rate of change.

f(3.5) = 25 means that:

$ab^{3.5} = 25$

$a = \frac{25}{b^{3.5}}$

f(8.5) = 14 means that:

$ab^{8.5} = 14$

Hence:

$\frac{25}{b^{3.5}} \times b^{8.5} = 14$

$25b^5 = 14$

$b = \sqrt[5]{\frac{14}{25}}$

$b = 0.89$

$a = \frac{25}{0.89^{3.5}} = 37.59$

Hence, the function is given by:

$y = 37.59(0.89)^x$

Then, when x = 5.5:

$f(5.5) = 37.59(0.89)^{5.5} = 19.8$

More can be learned about exponential functions at brainly.com/question/25537936

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Answer:

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Answer:

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Step-by-step explanation:

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