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atroni [7]
3 years ago
12

Need help with a math question

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

There are 10 possible ways the student can schedule the three classes

Step-by-step explanation:

The college student is choosing 3 classes to take during the first, second, and third semester from 5 electives.

Therefore, the student is choosing 3 items from a total of 5 and the order is not of key concern here. This is thus a combination problem;

5C3 = 10

read as 5 choose 3

The above mathematical operation can be performed using any modern calculator.

You might be interested in
At a large nursery, a border for a rectangular garden is being built. Designers want the border’s length to be 5 feet greater th
Salsk061 [2.6K]

Let

x--------> the border’s length

y--------> the border’s width

P--------> perimeter of the border


we know that

x=5+y------> equation 1

P=2*[x+y]-----> P=2x+2y

P <=180 ft

(2x+2y) <= 180-------> equation 2


substitute the equation 1 in equation 2

2*[5+y]+2y <= 180

10+2y+2y <= 180

4y <= 180-10

4y <=170

y <=42.5 ft

so

the maximum value of the width is 42.5 ft

for y=42.5 ft

x=42.5+5------> x=47.5 ft


the answer is

the width of the border is less than or equal to 42.5 ft


6 0
3 years ago
Evaluate f(−1)=−3x^3 + 2x^2
Sholpan [36]

Answer:

5

Step-by-step explanation:

f(-1)= -3(-1)³+2(-1)²

= -3(-1)+2(1)

= 3+2

=5

5 0
3 years ago
Giving anyone who can answer CORRECTLY brainless don’t comment if you don’t know I’ll flag you
Scrat [10]

Answer:

its proportional bc

Step-by-step explanation:

4.2 ÷3=1.4 and if you go 5 x 1.4 you get 7 same with the last one sorry im bad at explaining but i hope this helped

3 0
3 years ago
Area of this shape with 2cm and 2cm and 4cm and 7cm
Annette [7]
18cm is the answer of this question
6 0
3 years ago
X^2-14x-4=0, solve by completing the square
REY [17]
The answer is: x = 7 - √53      or      x = 7 + √53

The general quadratic equation is: ax² + bx + c  = 0.
But, by completing the square we turn it into: a(x + d)² + e = 0, where:<span>
d = b/2a
e = c - b²/4a
Our quadratic equation is x² - 14x -4 = 0, which is after rearrangement:
So, a = 1, b = -14, c = -4
Let's first calculate d and e:
d = b/2a = -14/2*1 = -14/2 = -7
e = c - b²/4a = -4 - (-14)</span>²/4*1 = -4 - 196/4 = -4 - 49 = -53<span>
By completing the square we have:
a(x + d)² + e = 0

1(x + (-7))</span>² + (-53) = 0
(x - 7)² - 53 = 0
(x - 7)² = 53
x - 7 = +/-√53
x = 7 +/- √53

Therefore, the solutions are:
x = 7 - √53
or
x = 7 + √53
4 0
3 years ago
Read 2 more answers
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