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3 years ago

Pls help me with these questions

Mathematics

1 answer:

KIM [24]3 years ago

5 0

Answer:

bald black man

Step-by-step explanation:

bald+black man, y=bbcx

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A software company is hiring some programmers to add to its development team. A junior programmer salary is $48,000 and a senior

emmainna [20.7K]

Answer:

$48,000x + 86,000y \leq 1,200,000$

Step-by-step explanation:

x is the number of junior programmers.

Each junior programmers costs $48,000.

So, the cost of x junior programmers is

48,000x

y is the number of senior programmers

Each senior programmer costs $86,000

So the cost of y seniors programmers is

86,000y

The total cost for x junior programmers and y seniors programmers is

48,000x + 86,000y

To keep costs down, the total spending on these new positions must be under $1,200,000 annually.

So the inequality is:

$48,000x + 86,000y \leq 1,200,000$

8 0

3 years ago

Can anyone help me with this please please please????

ycow [4]

Adjecent angles are angles that are right next to each others
The only ones that store are ihk and ghk

6 0

3 years ago

Read 2 more answers

5a+c=-8a, for a how do you solve this problem?

BaLLatris [955]

The answers is A= C/-13

C= 13A

8 0

3 years ago

Simplify f(x)=(x+1)(x-3) to standard form

Ivahew [28]

Answer:

x^2-2x-3

Explanation: Use FOIL

4 0

4 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

3 years ago