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Ludmilka [50]
3 years ago
8

The slope of a line is 0. What do you know about the line?

Mathematics
1 answer:
vekshin13 years ago
8 0

The answer is B. The line is horizontal. If the line was a regular diagonal slope line with a slope of 1, 2, etc., the answer would be A. If the slope was undefined, the line would be vertical. Since the slope is 0, the line doesn't increase in height or have a slope at all. It is simply a straight, horizontal line.

I hope this helps :)

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5 0
2 years ago
Why is "You are a ray of sunshine" a metaphor? Start your answer with 'You are a ray of sunshine" is a metaphor because a simile
PSYCHO15rus [73]

Answer:

You are a ray of sunshine is a metaphor because a simile has to have like or as in it.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Gregory’s age is 5 years greater than of Amanda’s age. Gregory is 17 years old. If Amanda’s age is denoted by x, which equation
Mariana [72]
Let Amanda's age = x.
Gregory's age = x + 5.

Since Gregory is 17 years old.
17 = x + 5
x = 17 - 5
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Amanda is 12 years old.
4 0
3 years ago
In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

6 0
3 years ago
The base of a cylindrical candle has an area of
Fudgin [204]

The volume of the cylindrical candle that has a base area of 12.56 inches is 12.56h inches³.

<h3>Volume of of cylinder</h3>

volume of a cylinder = πr²h

where

  • r = radius
  • h = height

Therefore,

volume of a cylinder = πr²h

Area of the base = πr²

Therefore,

Area of the base = 12.56 inches²

volume of the cylindrical candle = 12.56h inches³

learn more on volume here: brainly.com/question/11459769

#SPJ1

7 0
2 years ago
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