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Aleksandr [31]
3 years ago
9

Which image shows a translation of the green quadrilateral JKLM three units to the right and one unit down?

Mathematics
2 answers:
podryga [215]3 years ago
8 0

Answer:

The second option shows the correct translation of 3 units to the right and 1 unit down.

Amiraneli [1.4K]3 years ago
7 0

Answer:

The second option!

Step-by-step explanation:

Start from the starting point "J" then more three units to the right and lastly move one unit down.

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An abstract sculpture in the form of a triangle has a base 21 meters and a height of 12 meters. Find the are of the triangle.
charle [14.2K]
The area of a triangle could be determined using the following formula
\boxed{a= \frac{1}{2} \times b \times h}

plug in the numbers
a =  \frac{1}{2} \times 21 \times 12
a =  \frac{1}{2} \times 252
a= \frac{252}{2}
a = 126

The area of the triangle is 126 square meters
8 0
3 years ago
Simplify (Are all division)<br><br>2+4i<br>3i<br><br>3+2i<br>4+i<br><br>2i^11
Alla [95]

We\ know:\ i=\sqrt{-1}\to i^2=-1

\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i

\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i

2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i


Used:\ (a+b)(a-b)=a^2-b^2

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Step-by-step explanation:

I did this one too but i don't if they changed the answer good luck I would double check

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Answer: $498.08

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